如何使用正确的工作目录从BAT文件启动PowerShell脚本? [英] How to start PowerShell script from BAT file with proper Working Directory?

问题描述

我正在尝试创建bat脚本，该脚本可以在适当的工作目录下启动与bat文件相同名称的PowerShell脚本.

I'm trying to create bat script that can start PowerShell script named the same as bat file in proper working directotry.

这就是我得到的:

@ECHO OFF
PowerShell.exe -NoProfile -Command "& {Start-Process PowerShell.exe -ArgumentList '-NoProfile -ExecutionPolicy Bypass -File ""%~dpn0.ps1""' -WorkingDirectory '%~dp0' -Verb RunAs}"
PAUSE

以这种方式传递工作目录无效.

Passing working directory this way does not work.

如何制作能够通过正常工作目录以及命令行参数的脚本?

How to make script that will pass proper working directroy and also command line arguments?

推荐答案

一种解决方法是使用以下命令让PowerShell脚本将目录更改为其自身的来源:

A workaround is to let the PowerShell script change the directory to it's own origin with:

Set-Location (Split-Path $MyInvocation.MyCommand.Path) 

作为第一个命令.

按照 mklement0 的提示:在PSv3 +中，使用更简单的方法:

As per mklement0s hint: In PSv3+ use the simpler:

Set-Location -LiteralPath $PSScriptRoot

或使用此目录打开相邻文件.

Or use this directory to open adjacent files.

$MyDir = Split-Path $MyInvocation.MyCommand.Path
$Content = Get-Content (Join-Path $MyDir OtherFile.txt)

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