批量-用百分比符号代替 [英] Batch - replacing with percent symbol

问题描述

我想用％"替换字符串中的"mod":
set string=%string:mod=x%
我应该输入什么作为"x"?

I want to replace "mod" in string with "%":
set string=%string:mod=x%
What I should input as "x"?

推荐答案

您可以通过启用延迟扩展来做到这一点，以便可以将!用作分隔符.然后，将百分号加倍可以将百分数表示为替换字符.

you can do that by enabling delayed expansion so you can use ! as delimiters. Then, doubling the percent sign allows to represent percent as a replacement char.

@echo off
setlocal enabledelayedexpansion

set string=12 mod 15
set string=!string:mod=%%!
echo %string%

结果

12 % 15

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