将命令输出保存到变量 [英] Save command output to variable

问题描述

在批处理文件中，我试图获取命令的输出并将其保存到变量中.

In a batch file, I am trying to fetch the output of a command and save it to a variable.

我的命令的目标是计算特定文件夹中的文件夹数量.

The goal of my command is to count the number of folders in a certain folder.

• 我无法使用这个答案，但我不想使用临时文件.

• I can't use the trick provided in this accepted answer because I would have to do cd path\to\my\folder to get to the current directory. Unfortunately, I can't do this command because path\to\my\folder is in fact a UNC path (\\path\to\my\folder), and cd \\some\UNC\path is not supported by the windows cmd.
• I am aware of this answer but I don't want to use a temporary file.

所以我尝试执行以下操作:

So I tried to do the following:

• 要获取文件夹数，请使用:

• To obtain the number of folders, I use:

dir \\path\to\my\folder | find /c "<REP>"

这很好用，并且给了我一个我期望的数字.

This works fine and returning me a number as I would expect.

要在批处理变量中检索此命令的输出，我尝试过:

To retrieve the output of this command in a batch variable, I tried:

FOR /F "TOKENS=*" %%i IN ('\\path\to\my\folder | find /c "<REP>"') DO 
SET value = %%i

但未成功，错误消息仍然存在...

But without success, the error message being...

|出乎意料.

| was unexpected.

...当我执行批处理文件时......

...when I execute the batch file and...

%% i是意外的.

%%i was unexpected.

当我尝试直接在命令窗口中执行命令时.我试图转义<REP>字符串(...find /c ""<REP>""') DO...)周围的引号，也得到了相同的错误.

when I try to execute the command directly in a command window. I tried to escape the quotes around the <REP> string (...find /c ""<REP>""') DO...), got me the same error.

我在正确的路径上检索变量中的输出吗?我应该怎么做才能解决错误消息?
或者也许有一种更简单的方法来在变量中设置命令输出?

Am I on the right path to retrieve the output in a variable? What should I do to resolve the error message?
Or maybe there is a simpler way to set a command output in a variable?

推荐答案

您可以使用您最初提到的答案.您不必在那里cd，但是您可以使用pushd，它将为UNC路径分配一个临时驱动器号，当您执行popd时，这些路径将被释放.

You can use the answer you first mentioned. You don't have to cd there, but you can use pushd which will allocate a temporary drive letter for UNC paths which will be released when you do a popd.

所以本质上:

pushd \\server\path
set count=0
for /d %%x in (*) do set /a count+=1
popd

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