通过重新排列原始文件名来重命名多个文件 [英] Renaming multiple files by rearranging the original file name

问题描述

我想重命名遵循相同命名约定的多个文件，唯一的变化是名称末尾的日期.

I want to rename multiple files that follow the same naming convention, the only variation is the date at the end of the name.

例如TRADARCASHROLLUP.GRPTIRHK.01052017.CSV我希望文件的新名称以日期开头，而不是01052017.TRADARCASHROLLUP.GRPTIRHK.CSV

For example TRADARCASHROLLUP.GRPTIRHK.01052017.CSV I would like the new name of the file to begin with the date instead 01052017.TRADARCASHROLLUP.GRPTIRHK.CSV

希望有人可以帮助我编写批处理脚本来实现这一目标.我看到了其他答案，但无法将其应用于此.

Was hoping someone could help me write a batch script to achieve this. I have seen other answers but not been able to apply them to this.

我尝试使用以下内容:

ls | %{ "C:\UBSTesting\Incoming\TRADARCASHROLLUP.GRPTIRHK*" $_.name ($_.name 
-replace '^(\w+).(\w+).(\w+)', '$3.$1.$2')}

推荐答案

，也将其标记为batch-file:

@echo off
setlocal enabledelayedexpansion
for %%a in (*.*.*.csv) do (
  for %%b in (%%~na) do (
    set new=%%~xb.%%~nb%%~xa
    ECHO !new:~1!
  )
) 

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