将结果集转换为字符串并将其放置在列表中 [英] Convert Resultset to string and place in list

问题描述

我正在尝试将列表中的值转换为普通字符串，例如

I'm trying to convert the values in my list to normal strings such as

listy = [['value1','value2','value3'],['value1','value2','value3'],[

我初始化了一个空列表listy = []，并使用find_all('a')找到了所有<a>并将其作为输出

I initialized an empty list listy = [] and found all the <a> using find_all('a') and produced this as output

listy = [[... <a>value1</a>, <a>value2</a>, <a>value3</a>, ...],[...<a>value4</a>, <a>value5</a>, <a>value6</a>, ...],[]]

我尝试使用item.find_all('a').string，但是却收到此错误.

I tried using item.find_all('a').string however I was given this error.

AttributeError: 'ResultSet' object has no attribute 'string'

意味着ResultSet不能转换为字符串.

Meaning the ResultSet cannot be converted to string.

然后我搜索如何将ResultSet转换为String

I then search how to convert ResultSet to String

我找到了unicode.join(u'\n', map(unicode,listy))

但是，当我尝试此操作时，出现此错误

However when I tried this i get this error

AttributeError: 'unicode' object has no attribute 'append'

我很可能会在附加列表以使我的原始列表出现错误时出现此错误

I most likely get this error when I appended the list to get my original listy

如何将find_all('a')转换为string类型并将其附加到列表中?

How could i convert the find_all('a') to string types and append them into a list?

我的XML文件:

<Z>
  <Y>
    <x>
      <a> value1 </a>
      <a> value2 </a>
      <a> value3 </a>
    </x>
  </Y>
  <Y>
    <x>
      <a> value4 </a>
      <a> value5 </a>
      <a> value6 </a>
    </x>
  </Y>
  <Y>
  </Y>
</Z>

我正在尝试创建以下格式的列表

I'm trying to create a list in the following format

listy = [['value1','value2','value3'],['value4','value5','value6'],[]]

推荐答案

您需要获取每个个人链接的字符串，而不是整个结果集的字符串.

You need to get the string of each individual link, not of the whole result set.

循环遍历集合并获取.string 每个元素:

Loop over the set and fetch .string per element:

[link.string for link in item.find_all('a')]

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