从还提到卧室数量的字符串中提取平方米的最佳方法是什么? [英] What would be the best way to extract square meters from a string that also mentions the amount of bedrooms?

问题描述

我正在尝试提取:

<div class="xl-surface-ch"> 
                            &nbsp;84 m²  &nbsp;&nbsp;&nbsp;2 bed.  
                        </div>

来自链接，问题是，我只需要该字符串中的"84"(有时也会超过2或3位数字).

from link the problem is, I only need the "84" in this string (they sometimes go over 2 or 3 digits as well).

增加的困难是有时没有提到平方米，这看起来像这样:

Added difficulty is that sometimes the square meters are not mentioned, which looks like this:

<div class="xl-surface-ch"> 
                             &nbsp;&nbsp;&nbsp;2 bed.  
                        </div>

在这种情况下，我需要返回0

and in that case I'd need to return a 0

我最大的尝试是:

    sqm = []
for item in soup.findAll('div', attrs={'class': 'xl-surface-ch'}):
    item = item.contents[0].strip()[0:4]
    item_clean = re.findall("[0-9]{2,4}", item)
    sqm.append(item_clean)

print(sqm)

但是，这似乎不起作用，也根本不是我为上述最终结果所需要的. 这是我通过代码得到的结果:

But this doesn't seem to work and won't be at all what I need for the end result as stated above. Here's the result I'm getting with my code:

[['84'], ['70'], ['80'], ['32'], ['149'], ['22'], ['75'], ['30'], ['23'], ['104'], [], ['95'], ['129'], ['26'], ['55'], ['26'], ['25'], ['28'], ['33'], ['210'], ['37'], ['69'], ['36'], ['19'], ['119'], ['20'], ['20'], ['129'], ['154'], ['25']]

您真的会对你们提供什么样的解决方案感兴趣，因为老实说我没有真正的解决方案，特别是因为您有时拥有的建筑没有sqm ...也许带有if语句?我现在无论如何都要尝试.

Would be really interested in what kinds of solution you guys cook up because I honestly think there isn't really a solution, especially since you sometimes have buildings without the sqm... maybe with an if statement? I'm going to try that right now anyhow.

先谢谢您！

推荐答案

import requests
from bs4 import BeautifulSoup

r = requests.get(
    'https://www.immoweb.be/en/search/apartment/for-sale/leuven/3000')
soup = BeautifulSoup(r.text, 'html.parser')

for item in soup.findAll('div', attrs={'class': 'xl-surface-ch'}):
    item = item.text.strip()
    if 'm²' in item:
        print(item[0:item.find('m')])
    else:
        item = 0
        print(item)

输出:

84 
70 
80 
32 
149 
22 
75 
30 
23 
104 
0
95 
129 
26 
55 
26 
25 
28 
33 
210 
37 
69 
36 
19 
119 
20 
20 
129 
154 
25 

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