如何指望用量角器端到端测试元素动态计 [英] How to expect dynamic count of elements in e2e tests using Protractor
问题描述
我目前正在写与量角器愚见角应用中的一些端到端的测试。
I'm currently writing some e2e tests for my humble Angular app with Protractor.
我的应用程序工作正常,单元测试通过了所有,用于端到端太......直到这一个:
My app works fine, unit tests passes all, e2e used too... until this one:
appE2ESpec.js
describe('adding an item', function() {
var items,
addItemButton,
startCount;
beforeEach(function() {
items = element.all(by.css('li.item'));
addItemButton = element(by.id('addItemButton'));
startCount = items.count();
});
it('should display a new item in list', function() {
addItemButton.click();
expect(items.count()).toEqual(startCount+1);
});
});
这是我怎么会写我的测试,但
This is how I would have written my test but,
的问题是:的items.count()返回一个承诺,的我知道的,但我不能设法迫使量角器来解决它。所以,我得到这样的:
The problem is: that items.count() returns a promise, I know that, but I can't manage to force Protractor to resolve it. So I get this:
Failures:
1) myApp adding an item should display a new item in list
Message:
Expected 6 to equal '[object Object]1'.
我已经试过:
items.count().then(function(count) {
startCount = count;
//console.log(startCount) --> "6" Perfect!
});
但得到在年底同样的结果......我不能把期望
到然后
,我想到了这一点。
But got the same result at the end... I can't put the expect
into the then
, I thought about that too.
- 我搜索到量角器的GitHub库的问题,计算器和谷歌AngularJs组。
附录:
的console.log(startCount)
输出这样的:
{ then: [Function: then],
cancel: [Function: cancel],
isPending: [Function: isPending] }
我可以写 .toEqual(6)
,但我不希望每次我需要改变我的应用程序启动状态重写我的测试。
I could have written .toEqual(6)
but I don't want to rewrite my test each time I need to change my app startup state.
你知道吗?在此先感谢!
Any idea? Thanks in advance!!
推荐答案
您需要解决的承诺,然后做断言。
You need to resolve the promise and then do the assertion.
量角器将解决您传递给期望()的承诺,但它不能将号码添加到一个承诺。您需要首先解决的承诺的值:
Protractor will resolve the promise that you pass to expect(), but it cannot add a number to a promise. You need to resolve the value of the promise first:
beforeEach(function() {
...
items.count().then(function(originalCount) {
startCount = originalCount;
});
});
it('should display a new item in list', function() {
...
expect(items.count()).toEqual(startCount+1);
});
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