java.math.BigInteger的问题 [英] Problems with java.math.BigInteger

问题描述

我在方法的开头有以下代码:

I have the following code at the head of a method:

BigInteger foo = BigInteger.valueOf(0);
BigInteger triNum = BigInteger.valueOf(0);

//set min value to 1*2*3*4*5*...*199*200.
BigInteger min = BigInteger.ONE;
BigInteger temp = BigInteger.ZERO;
for(int i=1; i<=200; i++)
{
    temp = BigInteger.valueOf(i);
    min = min.multiply(temp);
}
System.out.println(min);

while(triNum.compareTo(min) <= 0)
{
    foo.add(BigInteger.ONE);
    triNum = triNum.add(foo);
    System.out.println("triNum: "+triNum);
}

这应该是将最小值加载到一个值(1 * 2 * 3 * ... * 199 * 200)，然后将triNum设置为第一个*三角形数字**，且其值大于min.

This is supposed to load a min to a value (1 * 2 * 3 * ... * 199 * 200), and then set triNum to the first *triangle number** with a value greater than min.

问题是，当我运行该方法时，我得到的只是一个终端窗口，该窗口带有"triNum:0"列表，一直在屏幕上向下滚动...我的代码中什么也看不到(尽管它完全是可能是我犯了一些错误，并且我对math.BigInteger有点不熟悉)，这似乎可以追溯到BigInteger类.有人在我的代码中看到错误了吗?

Problem is, when I run the method, all I get is a terminal window with a list of "triNum: 0" ever scrolling down the screen... I don't see anything in my code (although it is completely possible I made some mistake, and I am somewhat unfamiliar with math.BigInteger), and this seems to point back to the BigInteger class. Anyone see a bug in my code?

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*三角形数字是可以通过以下方式获得的数字:1 + 2 + 3 + 4 + 5 + 6 + 7 + ...

*A triangle number is a number that can be reached by: 1+2+3+4+5+6+7+...

推荐答案

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foo.add(BigInteger.ONE);

此更新foo吗?还是创建一个等于foo+ BigInteger.ONE且不再使用的对象?

Does this update foo? Or does it create an object that's equal to foo+ BigInteger.ONE which is not used again?

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