如何计算BitSet对象中的总位数? [英] How to calculate total number of bits in BitSet object?

问题描述

我想计算BitSet对象中的位数.方法length返回BitSet的逻辑大小":BitSet中最高设置位的索引加1，而方法cardinality将给出对象中设置为1的总位数

I want to calculate the total number of bits in a BitSet object. The method length returns the "logical size" of the BitSet: the index of the highest set bit in the BitSet plus one, while method cardinality will give the total number of bits set to 1 in the object.

我想计算包括0和1在内的总位数.我该怎么办?

I want to calculate the total number of bits including both 0s and 1s. How do I do that?

推荐答案

How about BitSet.size()?.....

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