如何在C中交换半字节? [英] How to swap nibbles in C?

问题描述

如何交换数字的半字节位置?

How to swap the nibble bit positions of a number?

例如:534，将其转换为二进制，最右边的4位必须与最左边的4位互换，然后使用该数字创建一个新的数字.

For example: 534, convert it into binary, the rightmost 4 bits has to be interchanged with the leftmost 4 bits and then make a new number with that.

有人知道该怎么做吗?

推荐答案

从十六进制0xf恰好覆盖四个位这一事实开始. 16位数字中有四个半字节.半字节的掩码为0xf000，0xf00，0xf0和0xf.然后开始屏蔽，移位和按位或"运算.

Start from the fact that hexadecimal 0xf covers exactly four bits. There are four nibbles in a 16-bit number. The masks for the nibbles are 0xf000, 0xf00, 0xf0, and 0xf. Then start masking, shifting and bitwise OR-ing.

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