如何旋转图像以保留其原始大小? [英] How to rotate an Image preserving its original size?

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问题描述

我一直在尝试旋转图像,但遇到了一些麻烦.第一个代码块在工作,但是会引起不良的副作用:旋转后,图像按比例缩小,因此x尺寸将与先前存在的y尺寸匹配.
因此,我旋转了图像,但它只占用了画布的一部分.

I have been attempting to rotate an Image and I have had some trouble with it. The first block of code was working, but it was causing an undesirable side effect: after the rotation, the Image was scaled down so that the x dimension would match the preexisting y dimension.
So I had the Image rotated, but it was only taking up part of the canvas.

为了解决这个问题,我认为我应该只创建一个更大的位图作为中间步骤,这样,当旋转它时,就不需要缩小图像来适应它.

In order to solve that, I figured I should just create a larger bitmap as an intermediate step, so that when it was rotated, the Image would not need to be shrunk in order to fit.

该代码在第二个块中.不幸的是,当我运行它时,出现了一般性的GDI错误.
有人知道我做错了吗?

That code is in the second block. Unfortunately when I run it, I get a generic GDI error.
Anyone know what I've done wrong?

作品:

Imports System.Drawing

If XSize < YSize Then 'Needs to be rotated
    Dim img As Image = Image.FromFile(strFilename)

    Dim b = New Bitmap(img.Height, img.Width)
    Dim gr As Graphics = Graphics.FromImage(b)
    img.RotateFlip(RotateFlipType.Rotate90FlipNone)
    gr.DrawImage(img, New Point(0, 0))
    img = Nothing
    b.Save(strFilename)
End If

此代码块不起作用:

'Needs to be rotated
If XSize < YSize Then 
    Dim img As Image = Image.FromFile(strFilename)
    Dim bmpTemp As Image

    If img.Height > img.Width Then
        bmpTemp = New Bitmap(img.Height, img.Height)
    Else
        bmpTemp = New Bitmap(img.Width, img.Width)
    End If

    Dim gr2 As Graphics = Graphics.FromImage(bmpTemp)
    gr2.DrawImage(img, New Point(0, 0))

    Dim b = New Bitmap(img.Height, img.Width)
    Dim gr As Graphics = Graphics.FromImage(b)
    bmpTemp.RotateFlip(RotateFlipType.Rotate90FlipNone)
    gr.DrawImage(bmpTemp, New Point(0, 0))
    img = Nothing
    b.Save(strFilename)
End If

推荐答案

我不太清楚您希望如何旋转图像.问题是旋转轴,旋转图像的新尺寸还是其他?

Not quite clear to me how would you like to rotate the image. Is the problem the rotation axis, the new size of the rotated image, or something else?

无论如何,据我所知,以下代码片段围绕画布的边缘或中心点旋转图像.

Anyways, to the best of my guessing, the following code snippet rotates the image either around the edges of the canvas or around it's center point.

Private Function RotateImage(ByVal src As Bitmap,
                            ByVal width As Integer,
                            ByVal height As Integer,
                            ByVal angle As Single,
                            Optional ByVal CenterRotation As Boolean = False) As Bitmap

   Dim cornors As Point() = {New Point(0, 0),
                        New Point(width, 0),
                        New Point(width, height),
                        New Point(0, height)}
   Using m As New Matrix
    If Not CenterRotation Then
        m.RotateAt(angle, New PointF(width / 2, height / 2))
        m.TransformPoints(cornors)
    End If

    Dim left = Integer.MaxValue
    Dim right = Integer.MinValue
    Dim top = Integer.MaxValue
    Dim bottom = Integer.MinValue

    For i = 0 To UBound(cornors)
        If cornors(i).X < left Then left = cornors(i).X
        If cornors(i).X > right Then right = cornors(i).X
        If cornors(i).Y < top Then top = cornors(i).Y
        If cornors(i).Y > bottom Then bottom = cornors(i).Y
    Next

    Dim b As New Bitmap(right - left, bottom - top)
    Dim x = (b.Width - width) / 2
    Dim y = (b.Height - height) / 2

    Using g As Graphics = Graphics.FromImage(b)
        m.Reset()
        m.RotateAt(angle, New PointF(b.Width / 2, b.Height / 2))
        g.Transform = m
        g.InterpolationMode = InterpolationMode.HighQualityBicubic
        g.SmoothingMode = SmoothingMode.HighQuality
        g.CompositingQuality = CompositingQuality.HighQuality
        g.Clear(Color.Transparent)
        g.DrawImage(src, New Rectangle(x, y, width, height))
    End Using
    Return b
   End Using
End Function

如果您还需要调整旋转图像的大小以适合画布,那么在第一个之后还需要以下代码:

If you also need to resize the rotated image to fit into the canvas, then you also need the following code AFTER THE FIRST ONE:

Private Function CreateThumbnail(ByVal bmp As Bitmap,
                                    ByVal canvasWidth As Integer,
                                    ByVal canvasHeight As Integer,
                                    Optional Stretch As Boolean = False) As Bitmap

    Dim bmpOut As Bitmap = Nothing

    If Stretch Then
        bmpOut = bmp.GetThumbnailImage(canvasWidth, canvasHeight, Nothing, IntPtr.Zero)
    Else
        Dim newWidth As Integer = 0
            Dim newHeight As Integer = 0

            bmpOut = New Bitmap(canvasWidth, canvasHeight)

            Dim ratioX As Double = CDbl(canvasWidth) / CDbl(bmp.Width)
            Dim ratioY As Double = CDbl(canvasHeight) / CDbl(bmp.Height)
            Dim ratio = If(ratioX < ratioY, ratioX, ratioY)

            newWidth = Convert.ToInt32(bmp.Width * ratio)
            newHeight = Convert.ToInt32(bmp.Height * ratio)

            If newWidth > bmp.Width Then
                newWidth = bmp.Width
            End If
            If newHeight > bmp.Height Then
                newHeight = bmp.Height
            End If

            Dim posX = Convert.ToInt32((canvasWidth - newWidth) / 2)
            Dim posY = Convert.ToInt32((canvasHeight - newHeight) / 2)

            Using g As Graphics = Graphics.FromImage(bmpOut)
                g.InterpolationMode = InterpolationMode.HighQualityBicubic
                g.SmoothingMode = SmoothingMode.HighQuality
                g.CompositingQuality = CompositingQuality.HighQuality
                g.Clear(Color.Transparent)
                g.DrawImage(bmp, posX, posY, newWidth, newHeight)
            End Using
        End If

    Return bmpOut
End Function

这是一个快速演示:

祝你好运.

这篇关于如何旋转图像以保留其原始大小?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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