使用C中的调色板数组查找最接近的RGB值 [英] Find nearest RGB value using color palette array in C
本文介绍了使用C中的调色板数组查找最接近的RGB值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我已经完成了部分代码，但是在某些比较中，最接近的值是错误的. 示例:
I have some part of code done, but in some comparisons, nearest values are incorrectly. Example:
正确:
Rgb value | Value from array
0xFFFFFD = 0xFFFFFF
错误: 固定代码
Rgb value | Value from array
0xF4F939 = 0xFF0000 (should be 0xFFFF00)
控制台输出:(正确)
C:\Users\honguito\Desktop\Bat\Game_Batch_Files\24_to_8_bitmap>24_to_8_bit_palett
e
The closest color of 0xFFFFFD is: '0xFFFFFF'
C:\Users\honguito\Desktop\Bat\Game_Batch_Files\24_to_8_bitmap>
控制台输出:(不正确)
C:\Users\honguito\Desktop\Bat\Game_Batch_Files\24_to_8_bitmap>24_to_8_bit_palett
e
The closest color of 0xF4F939 is: '0xFF0000'
C:\Users\honguito\Desktop\Bat\Game_Batch_Files\24_to_8_bitmap>
这些RGB颜色代码在数组中列出:
Those RGB color code are listed in an array:
int data[] = {
0x000000, 0x800000, 0x008000, 0x808000, 0x000080, 0x800080, 0x008080,
0xC0C0C0, 0xC0DCC0, 0xA6CAF0, 0x402000, 0x602000, 0x802000, 0xA02000,
0xC02000, 0xE02000, 0x004000, 0x204000, 0x404000, 0x604000, 0x804000,
0xA04000, 0xC04000, 0xE04000, 0x006000, 0x206000, 0x406000, 0x606000,
0x806000, 0xA06000, 0xC06000, 0xE06000, 0x008000, 0x208000, 0x408000,
0x608000, 0x808000, 0xA08000, 0xC08000, 0xE08000, 0x00A000, 0x20A000,
0x40A000, 0x60A000, 0x80A000, 0xA0A000, 0xC0A000, 0xE0A000, 0x00C000,
0x20C000, 0x40C000, 0x60C000, 0x80C000, 0xA0C000, 0xC0C000, 0xE0C000,
0x00E000, 0x20E000, 0x40E000, 0x60E000, 0x80E000, 0xA0E000, 0xC0E000,
0xE0E000, 0x000040, 0x200040, 0x400040, 0x600040, 0x800040, 0xA00040,
0xC00040, 0xE00040, 0x002040, 0x202040, 0x402040, 0x602040, 0x802040,
0xA02040, 0xC02040, 0xE02040, 0x004040, 0x204040, 0x404040, 0x604040,
0x804040, 0xA04040, 0xC04040, 0xE04040, 0x006040, 0x206040, 0x406040,
0x606040, 0x806040, 0xA06040, 0xC06040, 0xE06040, 0x008040, 0x208040,
0x408040, 0x608040, 0x808040, 0xA08040, 0xC08040, 0xE08040, 0x00A040,
0x20A040, 0x40A040, 0x60A040, 0x80A040, 0xA0A040, 0xC0A040, 0xE0A040,
0x00C040, 0x20C040, 0x40C040, 0x60C040, 0x80C040, 0xA0C040, 0xC0C040,
0xE0C040, 0x00E040, 0x20E040, 0x40E040, 0x60E040, 0x80E040, 0xA0E040,
0xC0E040, 0xE0E040, 0x000080, 0x200080, 0x400080, 0x600080, 0x800080,
0xA00080, 0xC00080, 0xE00080, 0x002080, 0x202080, 0x402080, 0x602080,
0x802080, 0xA02080, 0xC02080, 0xE02080, 0x004080, 0x204080, 0x404080,
0x604080, 0x804080, 0xA04080, 0xC04080, 0xE04080, 0x006080, 0x206080,
0x406080, 0x606080, 0x806080, 0xA06080, 0xC06080, 0xE06080, 0x008080,
0x208080, 0x408080, 0x608080, 0x808080, 0xA08080, 0xC08080, 0xE08080,
0x00A080, 0x20A080, 0x40A080, 0x60A080, 0x80A080, 0xA0A080, 0xC0A080,
0xE0A080, 0x00C080, 0x20C080, 0x40C080, 0x60C080, 0x80C080, 0xA0C080,
0xC0C080, 0xE0C080, 0x00E080, 0x20E080, 0x40E080, 0x60E080, 0x80E080,
0xA0E080, 0xC0E080, 0xE0E080, 0x0000C0, 0x2000C0, 0x4000C0, 0x6000C0,
0x8000C0, 0xA000C0, 0xC000C0, 0xE000C0, 0x0020C0, 0x2020C0, 0x4020C0,
0x6020C0, 0x8020C0, 0xA020C0, 0xC020C0, 0xE020C0, 0x0040C0, 0x2040C0,
0x4040C0, 0x6040C0, 0x8040C0, 0xA040C0, 0xC040C0, 0xE040C0, 0x0060C0,
0x2060C0, 0x4060C0, 0x6060C0, 0x8060C0, 0xA060C0, 0xC060C0, 0xE060C0,
0x0080C0, 0x2080C0, 0x4080C0, 0x6080C0, 0x8080C0, 0xA080C0, 0xC080C0,
0xE080C0, 0x00A0C0, 0x20A0C0, 0x40A0C0, 0x60A0C0, 0x80A0C0, 0xA0A0C0,
0xC0A0C0, 0xE0A0C0, 0x00C0C0, 0x20C0C0, 0x40C0C0, 0x60C0C0, 0x80C0C0,
0xA0C0C0, 0xFFFBF0, 0xA0A0A4, 0x808080, 0xFF0000, 0x00FF00, 0xFFFF00,
0x0000FF, 0xFF00FF, 0x00FFFF, 0xFFFFFF
};
然后获取我最近的数字:
Then to get the nearest number I do:
nearest = findKey(data, pcolor);
这是完整的代码:
#include <stdio.h>
int main () {
//int pcolor = 0xF4F939;
int pcolor = 0xFFFFFD;
//int pcolor = 0x700000;
//int pcolor = 0x21A0C0;
int cmp[256];
int cmp2[256];
int data[] = {
0x000000, 0x800000, 0x008000, 0x808000, 0x000080, 0x800080, 0x008080,
0xC0C0C0, 0xC0DCC0, 0xA6CAF0, 0x402000, 0x602000, 0x802000, 0xA02000,
0xC02000, 0xE02000, 0x004000, 0x204000, 0x404000, 0x604000, 0x804000,
0xA04000, 0xC04000, 0xE04000, 0x006000, 0x206000, 0x406000, 0x606000,
0x806000, 0xA06000, 0xC06000, 0xE06000, 0x008000, 0x208000, 0x408000,
0x608000, 0x808000, 0xA08000, 0xC08000, 0xE08000, 0x00A000, 0x20A000,
0x40A000, 0x60A000, 0x80A000, 0xA0A000, 0xC0A000, 0xE0A000, 0x00C000,
0x20C000, 0x40C000, 0x60C000, 0x80C000, 0xA0C000, 0xC0C000, 0xE0C000,
0x00E000, 0x20E000, 0x40E000, 0x60E000, 0x80E000, 0xA0E000, 0xC0E000,
0xE0E000, 0x000040, 0x200040, 0x400040, 0x600040, 0x800040, 0xA00040,
0xC00040, 0xE00040, 0x002040, 0x202040, 0x402040, 0x602040, 0x802040,
0xA02040, 0xC02040, 0xE02040, 0x004040, 0x204040, 0x404040, 0x604040,
0x804040, 0xA04040, 0xC04040, 0xE04040, 0x006040, 0x206040, 0x406040,
0x606040, 0x806040, 0xA06040, 0xC06040, 0xE06040, 0x008040, 0x208040,
0x408040, 0x608040, 0x808040, 0xA08040, 0xC08040, 0xE08040, 0x00A040,
0x20A040, 0x40A040, 0x60A040, 0x80A040, 0xA0A040, 0xC0A040, 0xE0A040,
0x00C040, 0x20C040, 0x40C040, 0x60C040, 0x80C040, 0xA0C040, 0xC0C040,
0xE0C040, 0x00E040, 0x20E040, 0x40E040, 0x60E040, 0x80E040, 0xA0E040,
0xC0E040, 0xE0E040, 0x000080, 0x200080, 0x400080, 0x600080, 0x800080,
0xA00080, 0xC00080, 0xE00080, 0x002080, 0x202080, 0x402080, 0x602080,
0x802080, 0xA02080, 0xC02080, 0xE02080, 0x004080, 0x204080, 0x404080,
0x604080, 0x804080, 0xA04080, 0xC04080, 0xE04080, 0x006080, 0x206080,
0x406080, 0x606080, 0x806080, 0xA06080, 0xC06080, 0xE06080, 0x008080,
0x208080, 0x408080, 0x608080, 0x808080, 0xA08080, 0xC08080, 0xE08080,
0x00A080, 0x20A080, 0x40A080, 0x60A080, 0x80A080, 0xA0A080, 0xC0A080,
0xE0A080, 0x00C080, 0x20C080, 0x40C080, 0x60C080, 0x80C080, 0xA0C080,
0xC0C080, 0xE0C080, 0x00E080, 0x20E080, 0x40E080, 0x60E080, 0x80E080,
0xA0E080, 0xC0E080, 0xE0E080, 0x0000C0, 0x2000C0, 0x4000C0, 0x6000C0,
0x8000C0, 0xA000C0, 0xC000C0, 0xE000C0, 0x0020C0, 0x2020C0, 0x4020C0,
0x6020C0, 0x8020C0, 0xA020C0, 0xC020C0, 0xE020C0, 0x0040C0, 0x2040C0,
0x4040C0, 0x6040C0, 0x8040C0, 0xA040C0, 0xC040C0, 0xE040C0, 0x0060C0,
0x2060C0, 0x4060C0, 0x6060C0, 0x8060C0, 0xA060C0, 0xC060C0, 0xE060C0,
0x0080C0, 0x2080C0, 0x4080C0, 0x6080C0, 0x8080C0, 0xA080C0, 0xC080C0,
0xE080C0, 0x00A0C0, 0x20A0C0, 0x40A0C0, 0x60A0C0, 0x80A0C0, 0xA0A0C0,
0xC0A0C0, 0xE0A0C0, 0x00C0C0, 0x20C0C0, 0x40C0C0, 0x60C0C0, 0x80C0C0,
0xA0C0C0, 0xFFFBF0, 0xA0A0A4, 0x808080, 0xFF0000, 0x00FF00, 0xFFFF00,
0x0000FF, 0xFF00FF, 0x00FFFF, 0xFFFFFF
};
int nearIndex,nearest, result;
nearest = findKey(data, pcolor);
printf("The closest color of 0x%X is: '0x%X'\n", pcolor, nearest);
//system("pause");
}
int findKey(int Array1[], int key){
int diff = abs( key - Array1[0]);
int Num1 = 0;
int Num2 = 0;
for (int a = 0; a < 256; a++) {
if (diff > abs( key - Array1[a] )) {
diff = abs( key - Array1[a]);
Num1 = Array1[a];
}
}
return Num1;
}
有一些未使用的变量和旧代码.
有什么想法吗?
推荐答案
要找到光学"最接近的颜色，您必须估算要比较的两种颜色的颜色分量之间的差异.
To find the "optical" closest color you have to estimate the difference between the color components of the two color you're comparing.
为此，您必须将24位值拆分为8位颜色分量r，g，b.
In order to do that you have to split the 24 bit value into 8 bit color components r, g, b.
然后比较组件.
一个简单的方法就是将各个分量之差的绝对值求和.
A naive method to do that is just sum the absolute value of the difference of the respective components.
我猜可以找到更准确的公式.
More accurate formulas can be found googling, I guess.
// two colors to compare
int c1;
int c2;
// split c1 and c2 into their respective color components
r1 = c1 / 0x010000;
g1 = (c1 % 0x010000) / 0x00100;
b1 = c1 % 0x000100;
r2 = c2 / 0x010000;
g2 = (c2 % 0x010000) / 0x00100;
b2 = c2 % 0x000100;
// color "distance"
diff = abs( r1 - r2 ) + abs( g1 - g2 ) + abs ( b1 - b2 );
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