针对多种类型检查变量的类型不会产生预期的结果 [英] Checking type of variable against multiple types doesn't produce expected result

问题描述

任务:

1. 使用一个参数定义函数distance_from_zero.
2. 让该函数执行以下操作:
   • 检查它收到的输入的类型.
   • 如果类型为int或float，则函数应返回函数输入的绝对值.
   • 如果类型是任何其他类型，则函数应返回"Not an integer or float!"

1. Define a function, distance_from_zero with one parameter.
2. Have that function do the following:
   • Check the type of the input it receives.
   • If the type is int or float, the function should return the absolute value of the function input.
   • If the type is any other type, the function should return "Not an integer or float!"

我的答案不起作用:

def distance_from_zero(d):
    if type(d) == int or float:
        return abs(d)
    else:
        return "Not an integer or float!"

推荐答案

您不能使用这种基于自然语言的逻辑串联".我的意思是，您需要明确说明逻辑条件的各个部分.

You cannot use this kind of "natural language based logic concatenation". What I mean is that you need to state the parts of your logical conditions explicitly.

if type(d) == int or type(d) == float

这样，您将拥有两个比较，它们分别代表:if type(d) == int和type(d) == float.可以将其结果与or运算符组合.

This way you have the two comparisons, which stand for themselves: if type(d) == int as well as type(d) == float. The results of this can be combined with the or-operator.

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