对应于std :: move的boost库 [英] the counterpart of std::move in boost library

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问题描述

我正在尝试在代码中使用std::move,但是我正在使用的编译器(g ++ 4.4)不支持它. boost::move可以完全替代std::move吗?谢谢.

I am trying to use std::move in my codes, but the compiler (g++ 4.4) I am using does not support it. Can boost::move substitute std::move completely? Thanks.

推荐答案

std::move(和启用了c ++ 0x支持的boost::move)仅仅是从T&T&&的转换.它实际上并没有移动任何东西.这意味着编译器必须支持指针T&&的特定类型. GCC从4.3版本开始支持r值引用,因此boost版本应该没问题.

std::move (and boost::move when c++0x support is enabled) is just a cast from T& to T&&. It does not actually move anything. This means that the specific type of pointer T&& must be supported by the compiler. GCC supports r-value references since version 4.3, so the boost version should be fine.

但是,为什么不能使用#include <utility>中的std::move?

However, is there a reason you can't use std::move from #include <utility>?

http://en.cppreference.com/w/cpp/utility/move

您只需要确保将-std=c++0x指定为编译器选项即可启用gcc 4.4的有限c ++ 11支持.

You just need to make sure to specify -std=c++0x as a compiler option in order to enable the limited c++11 support that gcc 4.4 has.

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