提高ptr_map替换值 [英] boost ptr_map replacing the value
本文介绍了提高ptr_map替换值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
给出一个键,我试图替换一个值.对于不使用指针的常规地图,我只使用了以下调用
Given a key, I am trying to replace a value. With regular maps, that do not use pointers, I simply used the following call
iter->second = object; //Where object was passed in by reference
如何使用boost :: ptr_map实现相同的目标?这里的概念是,我们使用派生对象替换整个类
How do I achieve the same with boost::ptr_map? The concept here is that we replace the entire class using the derived_object
iter->second = derived_object; //derived_object is a base_object pointer
推荐答案
这可以解决问题:
the_map.replace(iter, derived_object);
the_map
当然是iter
指向的地图.
请注意,ptr_map<K,V>::replace
返回一个ptr_map<K,V>::auto_type
,因此您可以根据需要获取被替换的对象.当然,如果您忽略它,它会被自动破坏,并且您永远不需要知道它在那里.
Note that ptr_map<K,V>::replace
returns a ptr_map<K,V>::auto_type
, so you can grab the replaced object if you want. Of course, if you ignore it, it's automagically destroyed and you need never know it was there.
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