如何将表单提交到Bootstrap模式(将POST方法发送到模式)Laravel [英] How to Submit Form into Bootstrap Modal (send POST method into Modal) Laravel

问题描述

我已经尝试了2天，但还是没有运气！

I have been trying for 2 days but still no luck!

我想

• 将表单从index.php提交到result.php
• 打开index.php时，在Modal中显示result.php！ (没有 关闭index.php)

• Submit Form from index.php to result.php
• Show result.php inside Modal while index.php is open! (without closing index.php)

这是示例代码！

index.php

index.php

<form id="myform" method="post" action="result.php" target="_blank">
<input type="text" name="userId" id="userId"/>
<input id="button" type="submit"/>
</form>

result.php

result.php

    <div id="resultModal" class="modal fade" tabindex="-1">
      <div class="modal-dialog">
        <div class="modal-content">
             <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-hidden="true">
                 <i class="fa fa-times-circle"></i>ESC</button>
                 <h4 class="modal-title">Show Result </h4>
            </div>
            <div class="modal-body">



            </div>

        </div>
    </div>
   </div>

在情态身体中

<?php  $selectedId = $_POST['userId']; 
    echo  $selectedId; 
?>

还有JQuery

<script type="text/javascript">

    $('#myForm').on('submit', function(ev) {
        var userId = $('#userId').find("input").val();
        $.ajax({
            type: 'POST',
            url : $(this).attr('action'),
            data: userId,
            success: function () {
              // alert('form was submitted');
            }
          });
});
</script>

推荐答案

嗯，我花了一些时间，但我想我已经找到了您问题的答案，或者至少此解决方案可以为您提供如何继续的好线索与你在做什么.

Well it has taken me some time but I think I found an answer to your question, or at least this solution can give you a good clue on how to continue with what you are doing.

第一个index.php:在这里，您需要具有一个带有输入字段和一个按钮的表单，我们将其称为模式表单，然后提交表单(使用Ajax进行发布)

First index.php: Here you need to have your form with an input field and one button, which we will call modal, and submit form (using Ajax for post)

<form id="form" method="post">
    <div id="userDiv"><label>UserId</label>
         <input type="text" name="userId" id="userId" placeholder="UserId"/> <br></div>
    <button type="button" id="btn" class="btn btn-info" data-toggle="modal" data-target="#myModal">Send Data</button>
</form>

然后，您需要一个模式，您可以在其中放置远程页面中的内容.在模态主体中，您再添加一个id为"bingo"的div标签，可以很容易地找到他:)，就像这样:

Then you need a modal where you will put content from remote page. In modal-body you add one more div tag with id="bingo" to locate him easy :) like this:

<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
  <div class="modal-dialog">
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
        <h4 class="modal-title" id="myModalLabel">MyModal</h4>
      </div>
      <div class="modal-body">
        <div id="bingo"></div>

      </div>
    </div>
   </div>
</div>

此页面还需要有一个脚本标签来完成这项工作. 重要，必须将其放置在加载jquery文件的脚本标签后 之后.

This page also needs to have a script tag which will do the job. Important it must be placed after the script tag where you load the jquery file.

<script>
    $(document).ready(function(){
        $("#btn").click(function(){
            var vUserId = $("#userId").val();
         if(vUserId=='')
         {
             alert("Please enter UserId");
         }
         else{
            $.post("result.php", //Required URL of the page on server
               { // Data Sending With Request To Server
                  user:vUserId,
               },
         function(response,status){ // Required Callback Function
             $("#bingo").html(response);//"response" receives - whatever written in echo of above PHP script.
             $("#form")[0].reset();
          });
        }
     });
   });
</script>

最后但并非最不重要的result.php:

And last but not the least result.php:

<?php
   if($_POST["user"])
   {
        $user = $_POST["user"];
       // Here, you can also perform some database query operations with above values.
       echo "Your user id is: ". $user;
  }
?>

P.S.我希望我不要把id，变量或类似的东西弄乱，因为我试图根据您的示例调整解决方案.我希望这是您所需要的，或者至少这将是完成任务的线索.仍然认为可以在一页上完成此操作，但是对我来说，尝试找到一种使之完成工作的方法很有趣... GL！

P.S. I hope I didn't mess somewhere with ids, variables or similar because I tried to adjust the solution to your example. I hope this is what you need, or at least this will be a clue to accomplish your task. Still think that this could be done on one page but it was interesting for me to try to find a way to make this work... GL!

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