当在Android手机上按返回按钮时如何关闭ui-bootstrap模态? [英] How to close ui-bootstrap modal when press back button on android phone?
问题描述
我有一个示例ui-bootstrap模式(来自ui-bootstrap文档)
I have a sample ui-bootstrap modal (from ui-bootstrap document)
angular.module('ui.bootstrap.demo', ['ui.bootstrap']);
angular.module('ui.bootstrap.demo').controller('ModalDemoCtrl', function ($scope, $modal, $log) {
$scope.items = ['item1', 'item2', 'item3'];
$scope.animationsEnabled = true;
$scope.open = function (size) {
var modalInstance = $modal.open({
animation: $scope.animationsEnabled,
templateUrl: 'myModalContent.html',
controller: 'ModalInstanceCtrl',
size: size,
resolve: {
items: function () {
return $scope.items;
}
}
});
modalInstance.result.then(function (selectedItem) {
$scope.selected = selectedItem;
}, function () {
$log.info('Modal dismissed at: ' + new Date());
});
};
$scope.toggleAnimation = function () {
$scope.animationsEnabled = !$scope.animationsEnabled;
};
});
// Please note that $modalInstance represents a modal window (instance) dependency.
// It is not the same as the $modal service used above.
angular.module('ui.bootstrap.demo').controller('ModalInstanceCtrl', function ($scope, $modalInstance, items) {
$scope.items = items;
$scope.selected = {
item: $scope.items[0]
};
$scope.ok = function () {
$modalInstance.close($scope.selected.item);
};
$scope.cancel = function () {
$modalInstance.dismiss('cancel');
};
});
<!doctype html>
<html ng-app="ui.bootstrap.demo">
<head>
<script src="//ajax.googleapis.com/ajax/libs/angularjs/1.3.13/angular.js"></script>
<script src="//angular-ui.github.io/bootstrap/ui-bootstrap-tpls-0.13.0.js"></script>
<script src="example.js"></script>
<link href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" rel="stylesheet">
</head>
<body>
<div ng-controller="ModalDemoCtrl">
<script type="text/ng-template" id="myModalContent.html">
<div class="modal-header">
<h3 class="modal-title">I'm a modal!</h3>
</div>
<div class="modal-body">
<ul>
<li ng-repeat="item in items">
<a ng-click="selected.item = item">{{ item }}</a>
</li>
</ul>
Selected: <b>{{ selected.item }}</b>
</div>
<div class="modal-footer">
<button class="btn btn-primary" ng-click="ok()">OK</button>
<button class="btn btn-warning" ng-click="cancel()">Cancel</button>
</div>
</script>
<button class="btn btn-default" ng-click="open()">Open me!</button>
<button class="btn btn-default" ng-click="open('lg')">Large modal</button>
<button class="btn btn-default" ng-click="open('sm')">Small modal</button>
<button class="btn btn-default" ng-click="toggleAnimation()">Toggle Animation ({{ animationsEnabled }})</button>
<div ng-show="selected">Selection from a modal: {{ selected }}</div>
</div>
</body>
</html>
打开一个模态后，当我在android设备上按向后按钮时，它会转到上一页，如何关闭模态而不是转到上一页?
After I open one modal, when I press back button on android device, it just go to previous page, how can I close the modal instead of go to previous page?
我花了很多时间，发现了很多类似这样的帖子(如何使用浏览器后退按钮关闭引导程序模式，而不是返回页?)，但是没有用.
I spent many hours and found many posts like this (how to close a bootstrap modal with the browser back button instead of going back a page?`), but it didn't work.
有解决方案吗?
谢谢.
推荐答案
Just came across this myself, and found a solution that works here. It requires the use of ui-router though. Put this in your run block:
.run([
'$rootScope', '$modalStack',
function ($rootScope, $modalStack) {
$rootScope.$on('$locationChangeStart', function (event) {
var top = $modalStack.getTop();
if (top) {
$modalStack.dismiss(top.key);
event.preventDefault();
}
});
}
])
这篇关于当在Android手机上按返回按钮时如何关闭ui-bootstrap模态?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
