Jabber bot-如何获取联系人的可用性? [英] Jabber bot - how to get the availability of contacts?

问题描述

我需要使用python设置一个jabber机器人，该机器人将根据多个联系人的在线/离线可用性发送消息.

I need to set up a jabber bot, using python, that will send messages based on the online/offline availability of several contacts.

我一直在研究pyxmpp和xmpppy，但找不到任何方法(至少没有直接方法)来检查给定联系人的状态.

I've been looking into pyxmpp and xmpppy, but couldn't find any way (at least nothing straightforward) to check the status of a given contact.

任何有关如何实现这一目标的指针?

Any pointers on how to achieve this?

理想情况下，我想要类似bot.status_of("[e-mail]")返回"online"

Ideally I would like something like e.g. bot.status_of("[e-mail]") returning "online"

推荐答案

我认为不可能以您想要的方式实现，因为联系人的存在(包含有关其可用性的信息)是由异步接收的机器人.

I don't think it is possible in the way you want it because the presence of contacts (which contains the information about their availability) is received asynchronously by the bot.

您将必须编写一个状态处理程序函数并将其注册到连接中.只要从联系人那里收到在线状态，就会调用此函数.呼叫参数将告诉您联系人是否在线.您可以根据需要将消息发送给联系人.

You will have to write a presence handler function and registered it with the connection. This function will get called whenever a presence is received from a contact. The parameter of the call will tell you if the contact is online or not. Depending upon it you can send the message to the contact.

使用xmpppy，您可以执行以下操作:

Using xmpppy you do it something like this:

def connect(jid, password, res, server, proxy, use_srv):
    conn = xmpp.Client(jid.getDomain())

    if not conn.connect(server=server, proxy=proxy, use_srv=use_srv):
        log( 'unable to connect to server.')
        return None

    if not conn.auth(jid.getNode(), password, res):
        log( 'unable to authorize with server.')
        return None

    conn.RegisterHandler( 'presence', callback_presence)
    return conn

conn = connect(...)

def callback_presence(sess, pres):
    if pres.getStatus() == "online":
        msg = xmpp.Message(pres.getFrom(), "Hi!")
        conn.send(msg)

PS:我尚未测试代码，但是应该与此非常相似.

PS: I have not tested the code but it should be something very similar to this.

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