C-如何读取输入 [英] C - How to read inputs

问题描述

这是家庭作业的一部分，但不是主要部分

it's part of the homework, but it's not the main part

我已经通过自己手动更改数据来实现了主要功能，但我确实没有

I already made the main function by manually changing the data by myself, but I really don't get how to read the user inputs correctly.

以下是输入内容：

3

1 2 9

6

1 1 3 4 4 6

1 1 3 4 4 6

0

因此，基本上，第一个输入是下一个输入的＃号的大小。因此，对于3，数组的大小为3，以[1,2,9]为元素，对于6，数组的大小为6，以[1,1,3,4,4,6]为元素

So basically the first input is the size of the # of the next inputs. So for 3, the array is size 3 with [1,2,9] being the elements, and for 6, the array size is 6 with [1,1,3,4,4,6] being the elements

当输入为0时，程序终止。

And when the input is 0, the program terminates.

我认为使用while循环并在输入时说[ 0] ='0'并中断，我可以终止程序，但是我不知道如何将其他输入转换为char数组。

I think by using a while loop and saying when input[0] = '0' and break, I can terminate the program, but I don't know how to get the other inputs into a char array.

您可以看到有空格，所以scanf会将每个整数读入char数组的方式都不同。

As you can see, there are spaces, so the scanf will read every integers differently into the char array.

获得了char的输入后，我相信可以使用atoi来将其恢复为整数...

After I get the inputs that are char, I believe I can use atoi to make it back to integers...

所以，请帮助我如何编码以便正确获取用户输入...

So, help me how I should code in order to get the user inputs correctly...

也许这太含糊了：这是我想要的版本：

Maybe this was too vague: here is the version I kinda want:

while(1)
{
    scanf("%d", &ui);

    if(ui == 0)
    {
        break;
    }
    else
    {   
        size = ui;
        int temp[size];

        for(c = 0; c < size; c++)
        {
            scanf("%d", &input);
            temp[c] = input;
        }
    }
}

输出对第一个数组，但是之后由于temp [size]，它输出一些奇怪的东西。有任何解决这个问题的方法吗？我希望数组的大小成为用户所需大小的大小。 （例如，对于我在上面编写的输入：3和6）

The output is good for the first array, but after that because of the temp[size], it outputs something weird. Any way to fix this? I want the size of the array to be the size of the user's wanted size. (e.g. for the input i've written above: 3 and 6)

推荐答案

抓取第一个数字应该是微不足道的，然后考虑要读取空格的数字字符串，您可以简单地使用 scanf（） 的否定扫描集：

Grabbing the first number should be trivial, then for the "string of numbers" considering you want to read spaces, you could simply do something like using scanf()'s negated scanset:

char input[100];
scanf("%99[^\n]", input);

或仅 fgets（）

char input[100];
fgets(input, sizeof input, stdin);

然后如您所料，将其放入期间循环等待第一个数字为0。

Then as you guessed put that in a while loop waiting for that first number to be 0.

>我相信我可以使用atoi将其恢复为整数

如果它们都是单个数字（如您的示例），您可以简单地从它们中减去'0'的值以获得 int 值

If they're all single digits (as in your example) you can simply subtract the value of '0' from them to get the int value

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