确定PHP字符串中的重复字符 [英] Determine repeat characters in a php string

问题描述

我发现了许多如何在字符串中查找重复字符的示例。我相信我的要求是独一无二的。

I have found many examples of how to find repeat characters in a string. I believe my requirement is unique.

我有字符串

$string=aabbbccddd;

我需要确定哪个字符重复最多。
因此，对于上面的示例，它会说
重复最多的字符是 B。
但是，在上面的示例中，B和D都重复了3次。
需要发现这一点。 B和D都重复了3次。

I need to determine which character was repeated the most. So for the above example it would say The character repeated the most is "B". However in the example above both B and D are repeated 3 times. Would need to spot that. B AND D are both repeated 3 times.

这是我到目前为止的内容。从我需要的但从起点开始的FAR

This is what I have so far. FAR from what I need but starting point

    <?php
$string = "aabbbccddd";
$array=array($array);
foreach (count_chars($string, 1) as $i => $val) {
$count=chr($i);
$array[]= $val.",".$count;
}
print_r($array);
?>

有人能帮助我吗？

推荐答案

基于georg的观点，我将使用正则表达式。这将使用数组键 dd => 2 和 ddd =处理拆分的重复项，例如 ddaaddd > 3 ，但在给定 ddaadd 时，只会显示 dd 的一项。要表示两者，则需要一个更复杂的数组：

Based on georg's great point, I would use a regex. This will handle split duplicates like ddaaddd with array keys dd=>2 and ddd=>3 but will only show one entry for dd when given ddaadd. To represent both would require a more complex array:

$string = "ddaabbbccddda";
preg_match_all('/(.)\1+/', $string, $matches);
$result = array_combine($matches[0], array_map('strlen', $matches[0]));
arsort($result);

如果您只需要计算所有出现次数，请尝试：

If you only need a count of ALL occurrences try:

$result = array_count_values(str_split($string));
arsort($result);

旧版答案：

如果您不这样做'没有重复的副​​本：

Legacy Answers:

If you don't have split duplicates:

$string  = 'aabbbccddd';
$letters = str_split($string);
$result  = array_fill_keys($letters, 1);
$previous = '';

foreach($letters as $letter) {
    if($letter == $previous) {
        $result[$letter]++;
    }
    $previous = $letter;
}
arsort($result);
print_r($result);

或者使用正则表达式：

preg_match_all('/(.)\1+/', $string, $matches);
$result = array_combine($matches[1], array_map('strlen', $matches[0]));
arsort($result);

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