如何从对象数组中删除所有重复对象？ [英] How to remove all dupes from an array of objects?

问题描述

// This is a large array of objects, e.g.:
let totalArray = [
    {"id":"rec01dTDP9T4ZtHL4","fields":
    {"user_id":170180717,"user_name":"abcdefg","event_id":516575,
    }]

let uniqueArray = [];

let dupeArray = [];

let itemIndex = 0

totalArray.forEach(x => {
  if(!uniqueArray.some(y => JSON.stringify(y.fields.user_id) === JSON.stringify(x.fields.user_id))){
    uniqueArray.push(x)
  } else(dupeArray.push(x))
})

node.warn(totalArray);
node.warn(uniqueArray);
node.warn(dupeArray);

return msg;

我正在成功地对数组进行重复数据消除以仅生成唯一值。问题是，我需要删除两个重复项，例如：如果有2个具有相同user_id键的对象，我想从数组中删除这两个对象，而不仅仅是一个。

I'm successfully deduping the array to produce only unique values. Problem is, I need to remove both duplicates, e.g.: if there are 2 objects with the same user_id key, I want to remove both of the objects from the array, not just one.

推荐答案

一种选择是遍历数组，并将当前要遍历的对象放在 user_id上属性。如果该属性已经存在，请将其重新分配为 null 。最后，获取对象的值并删除空值：

One option is to iterate over the array and put the current object being iterated over at a user_id property on the object. If the property already exists there, reassign it to null instead. At the end, take the values of the object and remove the null values:

const totalArray = [{
  "id": "rec01dTDP9T4ZtHL4",
  "fields": {
    "user_id": 170180717,
    "user_name": "abcdefg",
    "event_id": 516575,
  }
}, {
  "id": "rec01dTDP9T4ZtHL4",
  "fields": {
    "user_id": 170180717,
    "user_name": "abcdefg",
    "event_id": 516575,
  }
}, {
  "id": "unique",
  "fields": {
    "user_id": 1234,
    "user_name": "abcdefg",
    "event_id": 516575,
  }
}];
const uniques = {};
for (const item of totalArray) {
  const prop = item.fields.user_id;
  uniques[prop] = uniques.hasOwnProperty(prop)
    ? null
    : item;
}
const output = Object.values(uniques).filter(Boolean);
console.log(output);

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