PHP preg_match与通配符 [英] Php preg_match with wild card characters

问题描述

我在数组中有一些邮政编码，其中包括这样的通配符

I have some zip code in an array which includes some wild card characters like this

$zip_codes = array( '12556', '765547', '234*', '987*' );
$target_zip = '2347890';

因此要检查目标zip是否已存在于数组中。我是这样

So to check whether the target zip is already present in the array. I am doing like this

foreach( $zip_codes as $zip ) {
  if ( preg_match( "/{$target_zip}.*$/i", $zip ) ) {
    echo 'matched';
    break;
  }
  else {
    echo 'not matched';
  }
}

但它根本不匹配邮政编码。有人可以告诉我这里的问题吗？

But its not matching the zip at all. Can someone tell me whats the issue here?

推荐答案

您需要打开 $ zip * 转换为。* （或者也许是）将c $ c>值转换为有效的正则表达式\d * ）；那么您可以针对 $ target_zip ：

You need to turn your $zip values into valid regular expressions by converting * into .* (or perhaps \d*); then you can test them against $target_zip:

$zip_codes = array( '12556', '765547', '234*', '987*' );
$target_zip = '2347890';

foreach( $zip_codes as $zip ) {
    echo $zip;
    if (preg_match('/' . str_replace('*', '.*', $zip) . '/', $target_zip)) {
        echo ' matched'. PHP_EOL;
        break;
    }
    else {
        echo ' not matched' . PHP_EOL;
    }
}

输出：

12556 not matched
765547 not matched
234* matched

在3v4l.org上进行演示

您尚未表明是否要让 $ zip_codes 中的值匹配整个 $ target_zip 值或只是它的一部分。上面的代码仅适用于部分代码（即 234 与 12345 匹配）；如果您不希望这样做，请将正则表达式的结构更改为：

You haven't indicated whether you want the value in $zip_codes to match the entire $target_zip value or just part of it. The code above will work for just part (i.e. 234 will match 12345); if you don't want that, change the regex construction to:

if (preg_match('/^' . str_replace('*', '.*', $zip) . '$/', $target_zip)) {

锚点将确保 $ zip 与整个 $ target_zip 匹配。

The anchors will ensure that $zip matches the entirety of $target_zip.

这篇关于PHP preg_match与通配符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！