如何解析为字符串到多维数组（正则表达式？） [英] How to parse to string to multidimensional array (regex?)

问题描述

我需要按块将数据传递到数组，我该怎么做？我需要使用正则表达式吗？我的脚本给了我错误，因为我无法根据需要将其分开。有人有什么想法吗？

I need to pass the data to an array by blocks, how can I make this? Do I need to use regex? My script gives me errors because I can not separate it as I wish. Does anyone have any ideas?

数据：

~0 
11111111
~1 
222222222
~2 
3333333333

        ~end 
~0 
aaaaaaaaaaa
~1 
bbbbbbbbbb
~2 
cccccccccc
~3 
ddddddddddd 

        ~end 



~0 
yyyyyyyyyyy
xxxxxxxx
ffffffffff
~1 
rrrrrrrrrrrr
        ~end 

我需要这样：

Array ( 
  [0] => Array
                (
                    [0] => 11111111

                    [1] => 222222222 

                    [2] => 3333333333 


                )

        ),

  [1] => Array
                (
                    [0] => aaaaaaaaaaa

                    [1] => bbbbbbbbbb 

                    [2] => cccccccccc 

                    [3] => ddddddddddd 
                )

        ),

  [2] => Array
                  (
                      [0] => yyyyyyyyyyy
xxxxxxxx
ffffffffff

                      [1] => rrrrrrrrrrrr 

                  )

          ),



)

我的代码（失败）：

$texto = "~0 
11111111
~1 
222222222
~2 
3333333333

        ~end 
~0 
aaaaaaaaaaa
~1 
bbbbbbbbbb
~2 
cccccccccc
~3 
ddddddddddd 

        ~end 



~0 
yyyyyyyyyyy
xxxxxxxx
ffffffffff
~1 
rrrrrrrrrrrr
        ~end";

preg_match_all("/(?ms)^~0.*?~end/", $texto, $coincidencias);

foreach ( $coincidencias[0] as $bloque ){
    preg_match_all("/\~.*\n/", $bloque, $sub_bloques);
    $hola[] = $sub_bloques;
}

推荐答案

这里是一种非正则表达式方式：将字符串分成几行，然后遍历它们。检查您指定的条件，并在满足条件的情况下将每一行添加到子数组中。然后，当到达〜end 行时，将子数组追加到主数组中。

Here is one non-regex way: split the string into lines and iterate over them. Check for the conditions you've specified and add each line to a sub-array if it meets the conditions. Then when you get to an ~end line, append the sub-array to the main array.

$sub_bloques = [];
$hola = [];

foreach(array_map('trim', explode("\n", $texto)) as $line) {
    if ($line && substr($line, 0, 1) !== '~') {
        $sub_bloques[] = $line;
    }
    if ($line == '~end') {
        $hola[] = $sub_bloques;
        $sub_bloques = [];
    }
}

---

对于正则表达式解决方案，首先在〜end 上展开以将正文分成多个部分，然后在这些部分上 preg_match_all 查找符合条件的行。

---

For a regex solution, start by exploding on ~end to break the main text into sections, then preg_match_all on the sections to find lines that meet your conditions.

foreach (explode('~end', $texto, -1) as $section) {
    preg_match_all('/\n *(?!~)(\w+)/', $section, $matches);
    if ($matches[1]) $result[] = $matches[1];
}

（?!〜）是排除在后的〜开头的行。也许有一种方法可以用一个很酷的正则表达式来完成整个工作，但是我并不那么擅长。

(?!~) is a a negative lookbehind to exclude lines that start with ~. Maybe there's some way to do the whole thing with one big cool regex, but I'm not that good at it.

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