从爆炸的字符串生成动态数组 [英] Generate dynamic array from exploded string

问题描述

我有一个字符串数组，其格式如下：

I have an array of strings that are formatted like this:

$strings = array(
   "/user",
   "/robot",
   "/user/1",
   "/user/2",
   "/user/2/test",
   "/robot/1"
);

我需要做的是当我<$ c $时将其转换为以下结构的数组c> print_r（）它：

Array
(
  [user] => Array (
    [1] => array(),
    [2] => Array (
      [test] => array()
    )
  [robot] => Array (
      [1] => array()
    )
)

我知道我需要用定界符 / 炸开原始字符串，但是我的问题是我该如何构建动态数组。

I know I need to explode the original string by delimiter /. However my problem is how do I then build the dynamic array.

请注意，字符串中可能有无限数量的斜杠。

Please note that the strings could potentially have an unlimited amount of slashes.

推荐答案

在遍历列表时，可以使用引用逐步构建数组。

You can use a reference to progressively build an array as you traverse through the list.

$strings = array(
   "/user",
   "/robot",
   "/user/1",
   "/user/2",
   "/user/2/test",
   "/robot/1"
);

$extracted = array();

foreach( $strings as $string )
{
  $pos =& $extracted;
  foreach( explode('/', ltrim($string, '/')) as $split )
  {
    if( ! isset($pos[$split]) )
    {
      $pos[$split] = array();
    }

    $pos =& $pos[$split];
  }
}

print_r($extracted);

此代码可能无法很好地处理空元素（例如， / user / / 4 ////// test ），具体取决于您的要求。

This code might not handle empty elements very well (e.g., /user//4//////test), depending on your requirements.

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