Java循环数组模式 [英] Java looping array pattern

问题描述

我想知道我是否可以在以下问题上获得一些帮助。我需要创建一个以某种格式显示其输出的数组，但是我似乎无法弄清楚如何真正做到这一点。用语言很难解释这种模式，所以我附上了一张可以展示它的图像。

I was wondering if I could get some help with the following problem. I need to create an array that displays its output in a certain format, but I cannot seem to figure out how to actually get it to do so. The pattern is a little difficult to explain in words so I've attached an image that would showcase it.

下面提供的代码在下面显示输出fashion：根据用户输入的数字，假设他们输入了4，输出将是以下4x4数组：

The code provided below displays the output in the following fashion: Depending on the number the user enters, lets assume they entered 4, the output would be the following 4x4 array:

1 2 3 4

8 7 6 5

9 10 11 12

9 10 11 12

16 15 14 13

16 15 14 13

这显然不是我试图实现的模式..因此，任何帮助将不胜感激！

this clearly is not the pattern I am trying to achieve.. so any help would be appreciated!

公共类Question2 {

public class Question2 {

public static void main(String[] args) {

//declare scanner
    Scanner keyboard = new Scanner (System.in);

//Prompt user to enter a digit greater than or equal to 3
    System.out.println("How many rows/columns do you want your array to have? (Must be at least 3):");

//read user input
    int num = keyboard.nextInt();

//place constraints on int num so that if it is less than 3, the program does not execute
    while(num<3 )
    {
        System.out.println("Lets's try this again....");
        System.out.println("How many rows/colums do you want your array to have? (Must be at least 3):");
        num = keyboard.nextInt();   
    }

    //2D array with number of rows and columns entered by user
    int[][] array = new int [num][num];
    int inc=1;

    for(int i=0;i<array.length;i++)
    {
        if(i%2 == 0){
            for(int j=0;j<array.length;j++)
            {
                array[i][j]=inc;
                inc++;
            }
        }
        else{
            for(int j=num-1;j>=0;j--)
            {
                array[i][j]=inc;
                inc++;
            }
        }
    }

            //display formatted output 
    String [][]stringConvertedTable= new String[num][num];

    for(int i=0; i<num; i++) {
        for(int j=0; j<num; j++) {
            stringConvertedTable[i][j]= Integer.toString(array[i][j]);
            System.out.print(stringConvertedTable[i][j] + "\t");
        }
        System.out.println("");

推荐答案

您可以通过应用$ p $

you can achieve the wrapping of the counter by applying the modulo operator with the size of the array

result[i][(k+i)%size] = counter++;

如何？

    final int size = 5;
    int[][] result = new int[size][size];

    //the logic
    int counter = 1;
    for(int i = 0; i < size; i++) {
        for(int k = 0; k < size; k++) {
            result[i][(k+i)%size] = counter++;
        }
    }

    //just the output
    for(int i = 0; i < size; i++) {
        boolean isFirst = true;
        for(int k = 0; k < size; k++) {
            if(isFirst)
                isFirst = false;
            else
                System.out.print(", ");
            System.out.print(result[i][k]);
        }
        System.out.println();
    }

输出

1, 2, 3, 4, 5
10, 6, 7, 8, 9
14, 15, 11, 12, 13
18, 19, 20, 16, 17
22, 23, 24, 25, 21

这篇关于Java循环数组模式的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！