用Python在2D数组中进行计数和计算 [英] Count and calculation in a 2D array in Python

问题描述

我有47个要使用以下格式的Python进行分析的数据集，并将数据存储在2D数组中：

I have 47 set of data to be analysised using Python with the following forma t and I stored the data in 2D array:

2104,3,399900 1600,3,329900 2400,3,369000...

I使用len函数打印存储在数组中的项目。 （上一个错误，并更改为以下代码。）

I use len function to print the item stored in array. (The previous one has made some mistake and change to following code.)

array: with open("abc.txt", "r") as ins: 
substrings = data.read().split()
array = [map(int, substring.split(',')) for substring in substrings]
print(len(array)[0])

我也想做的一部分对于像athos格式的数组中的每个a，b和c进行如下计算：

A part from that I also would like to do some calculation like this for each a, b and c in array like thos format:

(2104-500)**2+(1600-500)**2+...
(3-2)**2+(3-2)**2...

我写道：

for [a for a, b, c in array] in range (len(array)[0]):
calculation_1 = ([a for a, b, c in array]) - 500)**2

for [b for a, b, c in array] in range (len(array)[1]):
calculation_2 = ([b for a, b, c in array]) - 2)**2

如何改进代码以提供所需的答案？

How can I improve the code to give the answer I want?

推荐答案

实际上，您有一个多维数组（[] []）。

In fact, you have a multi-dimension array ([][]).

数组的len确实是一个，但是如果这样做

The len of array is really one, but if do this

len(array[0])

应为95。

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