将不同类型的通用对象添加到通用列表中 [英] Adding different type of generic objects into generic list

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问题描述

是否可以将不同类型的通用对象添加到列表中?如下。

Is it possible to add different type of generic objects to a list?. As below.

public class ValuePair<T>
{        
    public string Name { get; set;}
    public T Value { get; set;                     
}

并说我拥有所有这些对象...

and let say I have all these objects...

 ValuePair<string> data1 =  new ValuePair<string>();
 ValuePair<double> data2 =  new ValuePair<double>();
 ValuePair<int> data3 =  new ValuePair<int>();

我想将这些对象保存在通用列表中,例如

I would like to hold these objects in a generic list.such as

List<ValuePair> list = new List<ValuePair>();

list.Add(data1);
list.Add(data2);
list.Add(data3);

有可能吗?

推荐答案

通常,您必须使用 List< object> 或创建非通用基类,例如

In general, you'd have to either use a List<object> or create a non-generic base class, e.g.

public abstract class ValuePair
{
    public string Name { get; set;}
    public abstract object RawValue { get; }
}

public class ValuePair<T> : ValuePair
{
    public T Value { get; set; }              
    public object RawValue { get { return Value; } }
}

然后,您可以拥有 List< ValuePair> ;

现在,有一个 例外:C#4中的协变/反变量类型。例如,您可以编写:

Now, there is one exception to this: covariant/contravariant types in C# 4. For example, you can write:

var streamSequenceList = new List<IEnumerable<Stream>>();

IEnumerable<MemoryStream> memoryStreams = null; // For simplicity
IEnumerable<NetworkStream> networkStreams = null; // For simplicity
IEnumerable<Stream> streams = null; // For simplicity

streamSequenceList.Add(memoryStreams);
streamSequenceList.Add(networkStreams);
streamSequenceList.Add(streams);

这不适用于您的情况,因为:

This isn't applicable in your case because:


  • 您正在使用泛型类,而不是接口

  • 您无法将其更改为泛型协变量接口,因为您有 T 进入了API的

  • 您将值类型用作类型参数,而这些值类型不适用于泛型变量(因此 IEnumerable< int> 不是 IEnumerable< object>

  • You're using a generic class, not an interface
  • You couldn't change it into a generic covariant interface because you've got T going "in" and "out" of the API
  • You're using value types as type arguments, and those don't work with generic variable (so an IEnumerable<int> isn't an IEnumerable<object>)

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