获取从不同程序集中执行的打开的Windows窗体实例的列表 [英] Get list of open windows form instance that are excuted from different assembly

问题描述

我有一个用于加载菜单的加载器应用，当用户单击菜单图像按钮时，将基于文本打开列表视图

I have a 'loader app' that loads a menu and when user clicks the menu image button a list view opens based on the text

(if text = employee)  
(Go to class A) 
(Go to class B) 
    ...
    ...
    (Show List View Window) 

如果他再次单击再次打开的相同按钮，我想防止这个。
，但对于WPF应用程序来说是这样的

if he clicks again on the same button it opens again, I would like to prevent this. i.e but this for a WPF application

推荐答案

如果您想要打开表单的列表，则为 Application.OpenForms 。您可以使用GetType（）并检查 .Assembly 来进行遍历，以从其他程序集中找到它们。除此之外，我还不清楚这个问题...

If you want a list of the open forms, that is Application.OpenForms. You could iterate over this, using GetType() and checking the .Assembly to find those from a different assembly. Beyond that, I'm not entire clear on the question...

        Assembly currentAssembly = Assembly.GetExecutingAssembly();
        List<Form> formsFromOtherAssemblies = new List<Form>();
        foreach (Form form in Application.OpenForms) {
            if (form.GetType().Assembly != currentAssembly) {
                formsFromOtherAssemblies.Add(form);
            }
        }

如果您只想跟踪表单，则可以自己打开，然后缓存该实例。或者，如果您使用拥有的表单，则只需按名称进行检查：

If you just want to track forms you have opened yourself, then cache that instance. Or if you use "owned forms", you can just check by name:

    private void button1_Click(object sender, EventArgs e) {
        foreach (Form form in OwnedForms) {
            if (form.Name == "Whatever") {
                form.Activate();
                return;
            }
        }
        Form child = new Form();
        child.Name = "Whatever";
        child.Owner = this;
        child.Show(this);
    }

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