使用单个接口注册多个实现 [英] Register multiple implementations with single interface
问题描述
是否有一种方法可以注册一个接口,该接口由多个具体类使用[simple-injector]而不使用模板接口来实现?
Is there a way to register a single interface which is implemented by more than one concrete class using [simple-injector] and without using template interface?
说我们有2个类 MyClass1
和 Myclass2
,这两个类都实现了 IInterface1
say we have 2 classes MyClass1
and Myclass2
and both these classes are implementing IInterface1
现在,我们无法使用[简单注射器]
Now using [simple-injector] we were not able to do this
container.Register<IInterface1, Myclass1>();
container.Register<IInterface1, Myclass2>();
将现有接口转换为模板接口在现有代码库上有点困难。希望有一些简单的方法。
converting existing interface to template interface is kinda a hard job on the existing codebase. Hoping there is some easier out there.
推荐答案
您可以使用 RegisterCollection
方法(请参见文档:配置集合
You can register multiple implementation of the same interface with using the RegisterCollection
method (see documentation: Configuring a collection of instances to be returned)
所以您需要编写:
container.Collection.Register<IInterface1>(typeof(Myclass1), typeof(Myclass2));
现在,简单注入器可以注入 Interface1 $ c $的集合c>实现到您的构造函数中,例如:
And now Simple Injector can inject a collection of Interface1
implementation into your constructor, for example:
public class Foo
{
public Foo(IEnumerable<IInterface1> interfaces)
{
//...
}
}
或者您可以使用 GetAllInstances
:
var myClasses = container.GetAllInstances<IInterface1>();
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