为什么gcc警告仅缩小统一初始化的转换范围? [英] Why gcc warns about narrowing conversion only for uniform initialization?
问题描述
我正在尝试使用 int
类型变量/en.cppreference.com/w/cpp/language/list_initialization rel = nofollow noreferrer> 统一初始化
,并且没有它。但是我只有在统一初始化时才收到编译器警告。这是为什么?为什么在两种情况下 gcc
都不发出警告?我也尝试过使用 clang
并获得类似的结果。
I am trying to convert long
type variable to int
type variable with uniform initialization
and without it. But I get compiler warning only with uniform initialization. Why is that? Why does not gcc
warn in both cases? I have tried with clang
also and got similar results.
这是代码
#include <iostream>
int main() {
long l = 1;
int i1 = l;
int i2 = { l };
std::cout << i1 << std::endl;
std::cout << i2 << std::endl;
return 0;
}
这是我得到的唯一警告
$ g++ -Wall -Wextra 1.cpp
1.cpp: In function ‘int main()’:
1.cpp:6:16: warning: narrowing conversion of ‘l’ from ‘long int’ to ‘int’ inside { } [-Wnarrowing]
int i2 = { l };
推荐答案
因为标准说,缩小转换限制仅用于列表初始化(自C ++ 11起)。
Because the standard says, narrowing conversions limit is specified only for list initialization (since C++11).
列表初始化限制
允许的隐式转换,禁止以下操作:
list-initialization limits the allowed implicit conversions by prohibiting the following:
- 从浮点类型转换为整数类型
- 从长整型转换为double或double,然后从double转换为float,除非source是一个常量表达式
,不会发生溢出 - 从整数类型到浮点类型的转换,除非source是一个可以存储值的常量表达式
完全符合目标类型 - 从整数或无作用域枚举类型到无法表示的整数类型的转换nt原始的所有值,除非源
是一个常数表达式,其值可以精确地存储在
目标类型中
- conversion from a floating-point type to an integer type
- conversion from a long double to double or to float and conversion from double to float, except where the source is a constant expression and overflow does not occur
- conversion from an integer type to a floating-point type, except where the source is a constant expression whose value can be stored exactly in the target type
- conversion from integer or unscoped enumeration type to integer type that cannot represent all values of the original, except where source is a constant expression whose value can be stored exactly in the target type
对于其他初始化方法(使用括号或等号),不应用缩小转换限制规则(添加);因为那样会破坏很多旧代码。
For the other initialization methods (using parentheses or equal sign), narrowing conversions limit rule is not applied (added); because that might break much legacy code.
这篇关于为什么gcc警告仅缩小统一初始化的转换范围?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!