C ++ 11：通过引用或值传递（lambda或其他）函数对象？ [英] C++11: pass (lambda or other) function object by reference or value?

问题描述

这最初是该问题的一部分：

This was originally part of this question:

Passing lambda declared using auto-keyword by non-const reference as argument to std::function parameter type

，但我决定将其分开。

在什么情况下通过lambda或其他方法更好/更惯用通过引用或值来获取函数对象？

In what circumstances is it better/more idiomatic to pass a lambda or other function object by reference or value?

推荐答案

您对 lambda使用与 any相同的规则作为参数的对象。

You use the same rules for "lambda"s that you would for any object that you take as a parameter.

如果函数的目的是为调用者修改对象，则函数应使用非常量引用。如果该函数只是使用对象而不更改它，则应使用 const& 。如果要将对象复制/移动到其内部存储中，则应该按值传递。

A function should use non-const reference if the intent of the function is to modify the object for the caller. The function should use const& if it is just using the object without changing it. And it should pass by value if it is going to copy/move the object into its internal storage.

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