如何使用QCoreApplication :: postEvent注入合成输入事件 [英] How to use QCoreApplication::postEvent to inject synthetic input events

问题描述

我正在将通过网络传入的键盘和鼠标事件注入Qt应用程序，并为此使用 QCoreApplication :: postEvent 。鼠标坐标是屏幕的绝对像素坐标。

I'm injecting Keyboard and Mouse events which are comming over the network into my Qt Application and use QCoreApplication::postEvent for this. The mouse coordinates are absolute screen pixel coordinates.

QMouseEvent *event = new QMouseEvent(type, QPoint(x, y), mouse_button, mouse_buttons,
    Qt::NoModifier);
QCoreApplication::postEvent(g_qtdraw.main.widget, event);

最初我只有一个小部件（由 g_qtdraw.main.widget <引用/ code>），因此我只是使用该变量作为 postEvent 的接收器参数。现在我的应用程序有多个小部件，上面的代码不再满足我的要求。

Initially I had just one widget (referenced by g_qtdraw.main.widget) so I simply used that one as the receiver argument for postEvent. Now my application has more than one widget and the above code does not do what I want any longer.

第二个小部件以全屏模式显示，我知道所有鼠标事件必须转到此窗口，但是使用上面的代码，它们仍然被路由到主窗口小部件。

A second widget is shown in fullscreen mode and I know that all mouse events have to go to this window but with the above code they are still routed to the main widget.

我如何选择正确的窗口小部件作为接收器（下一个鼠标x，y坐标）？有没有一种标准的方法，以便Qt选择正确的小部件，或者我必须自己跟踪此小部件？

How do I choose the correct widget as the receiver (the one under the mouse x,y coords)? Is there a standard way, so that Qt chooses the right widget or do I have to track this myself?

推荐答案

您可以使用 QApplication :: widgetAt（） 在该位置找到正确的小部件，然后发布到该位置？

Can you use QApplication::widgetAt() to find the correct widget at the position and then post to that?

QPoint pos(x, y);
QMouseEvent *event = new QMouseEvent(type, pos, mouse_button, mouse_buttons,  Qt::NoModifier);
QWidget *receiver = QApplication::widgetAt(pos);
QCoreApplication::postEvent(receiver, event);

我不希望您在关键事件中必须这样做。它们应该发送到焦点小部件（ QApplication :: focusWidget（））。

I wouldn't expect that you would have to do this for the key events though. They should be sent to the focused widget (QApplication::focusWidget()).

不幸的是，我还没有t测试了其中任何一个。

Unfortunately, I haven't tested any of this.

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