`std :: pair` second`的类型不完整,带有`unordered_map`树 [英] `std::pair` `second` has incomplete type with `unordered_map` tree
问题描述
我正在查看我的一些较旧的代码,并且看到了使用指针来实现 Variant
对象树的代码。这是一棵树,因为每个 Variant
可以包含 Variant * $ c的
unordered_map
$ c>。
I was reviewing some older code of mine and I saw the code using pointers to implement a tree of Variant
objects. It is a tree because each Variant
can contain an unordered_map
of Variant*
.
我看了一下代码,想知道为什么不只使用值,一个 std :: vector< Variant>
和 std :: unordered_map< std :: string,Variant>
,而不是 Variant *
。
I looked at the code and wondered why isn't it just using values, a std::vector<Variant>
, and std::unordered_map<std::string, Variant>
, instead of Variant*
.
所以我继续进行了更改。似乎没事,只有一件事,我错误:
So I went ahead and changed it. It seemed okay except one thing, I got errors:
/usr/local/include/c++/6.1.0/bits/stl_pair.h:153:11: error: 'std::pair<_T1, _T2>::second' has incomplete type
_T2 second; /// @c second is a copy of the second object
^~~~~~ main.cpp:11:8: note: forward declaration of 'struct Variant'
struct Variant
^~~~~~~
所以我想我可以欺骗导致编译器延迟了对这种类型的了解,而也不起作用。
So I figured I could trick the compiler into delaying the need to know that type, which didn't work either.
我以为这早一点可行了,但实际上却没有,我使用HideMap在上忘记了
:: type
...
#include <vector>
#include <unordered_map>
#include <iostream>
template<typename K, typename V>
struct HideMap
{
using type = std::unordered_map<K, V>;
};
struct Variant
{
using array_container = std::vector<Variant>;
// Does not work either
using object_container = typename HideMap<std::string, Variant>::type;
// Fails
//using object_container = std::unordered_map<std::string, Variant>;
private:
union Union
{
std::int64_t vint;
array_container varr;
object_container vobj;
// These are required when there are union
// members that need construct/destruct
Union() {}
~Union() {}
};
Union data;
bool weak;
};
int main()
{
Variant v;
std::cout << "Works" << std::endl;
}
所以,我的问题是,为什么<$ c $可以正常工作c> vector 而不是 unordered_map
?
So, my question is, why does it work okay for vector
and not unordered_map
?
如果问题是无法使用不完整的类型,是否有办法延迟 unordered_map
的实例化?我真的不希望每个对象属性都是单独的 new
分配。
If the problem is the inability to use incomplete types, is there a way to delay the instantiation of the unordered_map
? I really don't want every object property to be a separate new
allocation.
推荐答案
这将使用new放置将 Union
的初始化推迟到构造函数,其中 Variant
是完整类型。您需要使用 Union
的任何地方 reinterpret_cast
。我努力不违反任何严格的对齐规则。
This uses placement new to defer the initialization of the Union
to the constructor where Variant
is a complete type. You need to reinterpret_cast
everywhere you need to use the Union
. I made an effort to not have any strict-alignment violations.
#include <algorithm>
#include <iostream>
#include <unordered_map>
#include <vector>
struct Variant {
Variant();
~Variant();
private:
std::aligned_union<0, std::vector<Variant>,
std::unordered_map<std::string, void *>,
std::int64_t>::type data;
};
namespace Variant_detail {
using array_container = std::vector<Variant>;
using object_container = std::unordered_map<std::string, Variant>;
union Union {
std::int64_t vint;
array_container varr;
object_container vobj;
// These are required when there are union
// members that need construct/destruct
Union() {}
~Union() {}
};
}
Variant::Variant() {
//make sure that std::unordered_map<std::string, Variant> is not too large
static_assert(sizeof(std::unordered_map<std::string, Variant>) <=
sizeof data, "Variant map too big");
static_assert(alignof(std::unordered_map<std::string, Variant>) <=
alignof(decltype(data)), "Variant map has too high alignment");
auto &my_union = *new (&data) Variant_detail::Union;
my_union.vint = 42;
}
Variant::~Variant() {
reinterpret_cast<Variant_detail::Union &>(data).~Union();
}
int main() {
Variant v;
std::cout << "Works" << std::endl;
}
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