按值传递数组 [英] Passing array by value

问题描述

是否可以将值数组传递给C ++函数？

Is it possible to pass an array by value to a C++ function?

如果是，我该怎么做？

推荐答案

如果用 array 表示原始 array ，那么答案是否。您无法在C或C ++中按值传递它们。

If by array you mean raw array, then the answer is No. You cannot pass them by value either in C or C++.

两种语言都提供了一种解决方法，您可以在其中包装 struct 围绕该数组并传递其对象。示例：

Both the languages provide a workaround, where you can wrap a struct around that array and pass its object. Example:

struct MyArray { int a[100]; };
...
struct MyArray obj; // `obj.a[]` is the array of your interest
foo(obj);  // you have passed the `a[]` by value

传递了`a []`在C ++中，这样的结构很容易获得格式为 std :: vector 和 std :: array 。

In C++, such structs are readily available in form of std::vector and std::array.

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