对于每个模板类型，设置类型的参数 [英] For every template type an argument of a set type

问题描述

说我有一个可变参数模板类。我该如何创建一个函数，使其参数为设置类型，例如 int ，并且参数数量等于模板类型的数量？

Say I have a variadic template class. How do I create a function such that it's arguments are of a set type, for example int, with the number of arguments being equal to the number of template types?

template <typename... Types>
class Test
{
public:
    void Func(???); // I don't know how to declare such a function
}

Test<string, bool, long> myTest; // Three types
myTest.Func(905, 36, 123315); // Three arguments, but always of type int.

最后，该函数的目标是返回提供的int的元组。为简单起见，我在示例代码中显示了该函数为空。

In the end, the goal of the function is to return a tuple of the provided ints. For simplicity I showed the function to be void in the example code.

推荐答案

template <typename... Types>
class Test
{
    template <typename>
    using int_t = int;

public:    
    void Func(int_t<Types>... ints)
    {
    }
};

演示

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