如何延长一个AngularJS资源($资源)的构造函数? [英] How can I extend the constructor of an AngularJS resource ($resource)?
问题描述
我有一个模型,使用 $资源
定义,我成功加载。
I have a model, defined using $resource
, that I am successfully loading.
每个加载实例,如许,我所定义的类的实例。
Each loaded instance is, as promised, an instance of the class I defined.
(下面的例子是从角文档。在这里面, User.get
导致一个对象,它是一个的instanceof用户
)
(The example below is from the Angular docs. In it, User.get
results in an object that is an instanceof User
.)
var User = $resource('/user/:userId', {userId:'@id'});
不过,想象每个用户过来这样的线:
However, imagine each User comes over the wire like this:
{
"username": "Bob",
"preferences": [
{
"id": 1,
"title": "foo",
"value": false
}
]
}
我定义了一个 preference
工厂,增加了有价值的方法,以 preference
的对象。但是,当用户负载,这些 preferences
不是 preference
S,自然。
I defined a Preference
factory that adds valuable methods to Preference
objects. But when a User loads, those preferences
aren’t Preference
s, naturally.
我试图这样的:
User.prototype.constructor = function(obj) {
_.extend(this, obj);
this.items = _.map(this.preferences, function(pref) {
return new Preference(pref);
});
console.log('Our constructor ran'); // never logs anything
}
但它没有任何效果,从来没有记录任何东西。
But it has no effect and never logs anything.
我怎样才能让每一个项目在我的用户
S' preferences
阵列<实例code> preference ?
How can I make each item in my User
s’ preferences
array an instance of Preference
?
推荐答案
$资源是一个简单的实现,并在事情没有这样的。
$resource is a simple implementation, and lacks in things like this.
User.prototype.constructor
不会做任何事情;角不会尝试像它的面向对象的,不像其他库。这只是JavaScript的。
User.prototype.constructor
won't do anything; angular doesn't try to act like it's object oriented, unlike other libraries. It's just javascript.
..但幸运的是,你必须承诺和JavaScript :-)。这里有一个方法,你可以做到这一点:
..But luckily, you have promises and javascript :-). Here's a way you could do it:
function wrapPreferences(user) {
user.preferences = _.map(user.preferences, function(p) {
return new Preference(p);
});
return user;
}
var get = User.get;
User.get = function() {
return get.apply(User, arguments).$then(wrapPreferences);
};
var $get = User.prototype.$get;
User.prototype.$get = function() {
return $get.apply(this, arguments).$then(wrapPreferences);
};
您可以抽象成装饰任何资源的方法,一种方法是:它需要一个对象,方法名称的数组和装饰功能
You could abstract this into a method which decorates any of a resource's methods: It takes an object, an array of method names, and a decorator function.
function decorateResource(Resource, methodNames, decorator) {
_.forEach(methodNames, function(methodName) {
var method = Resource[methodName];
Resource[methodName] = function() {
return method.apply(Resource, arguments).$then(decorator);
};
var $method = Resource.prototype[methodName];
Resource.prototype[methodName] = function() {
return $method.apply(this, arguments).$then(decorator);
};
});
}
decorateResource(User, ['get', 'query'], wrapPreferences);
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