是否可以在C ++中获取std :: array的子​​数组？ [英] Is it possible to get a sub-array of a std::array in C++?

问题描述

我想做类似的事情

std::array<int, 5> array1 = {{ ... }};
const std::array<int, 3>& array2 = array1[1:4]; // [x:y] doesn't exist

也就是说，得到一个排序数组

That is, get an array that is a sort of view of another array, without having to copy it.

推荐答案

不，您不能那样做。所有标准库容器都是其数据的唯一所有者， std :: array 也不例外。实际上， std :: array 被限制为以某种方式实现，以便将元素存储在类的实际数组成员中，这将使别名变得不可能。

No, you can't do that. All standard library containers are unique owners of their data, and std::array is no exception. In fact, std::array is constrained to be implemented in such a way so that the elements are stored inside an actual array member of the class, which would make aliasing impossible.

有一个关于 array_view 类的建议，该类表示对连续数据块的非所有权视图。您可以在此处进行阅读。我不知道此提案的状态（当前的C ++标准化过程使我感到困惑）。

There is a proposal for an array_view class that would represent a non-owning view into a contiguous block of data. You can read about it here. I don't know the status of this proposal (the current C++ standardization process confuses me).

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