AngularJS：如何清除URL查询参数？ [英] AngularJS: How to clear query parameters in the URL?

问题描述

我的AngularJS应用程序需要访问用户的LinkedIn的个人资料。为了做到这一点，我需要将用户重定向到包含一个回调REDIRECT_URI参数它会告诉LinkedIn将用户重定向回到我的web应用程序，并在URL中包括一个code查询参数一个LinkedIn URL。这是一个传统的OAuth 2.0用户流量。

My AngularJS application needs to have access to the user's LinkedIn profile. In order to do that I need to redirect the user to a LinkedIn URL which contains a callback redirect_uri parameter which will tell LinkedIn to redirect the user back to my webapp and include a "code" query param in the URL. It's a traditional Oauth 2.0 flow.

除了LinkedIn用户重定向到以下网址一切都很正常：

Everything works great except that LinkedIn redirects the user back to the following URL:

http://localhost:8080/?code=XXX&state=YYY#/users/123/providers/LinkedIn/social-sites

我想删除 code = XXX＆放大器;从URL状态= YYY 为了使干净？用户不需要看我从LinkedIn收到的查询参数重定向。

I would like to remove ?code=XXX&state=YYY from the URL in order to make it clean. The user does not need to see the query parameters I received from LinkedIn redirect.

我试过 $ location.absUrl（$ location.path（）+ $的location.hash（））。REPLACE（），但保留在该查询参数网址。

I tried $location.absUrl($location.path() + $location.hash()).replace(), but it keep the query params in the URL.

我也无法提取查询参数，例如code，使用（$ location.search（））。code 。
好像有？ ＃在URL之前上面淋水角。

I am also unable to extract the query parameters, e.g. "code", using ($location.search()).code. It seems like having ? before # in the URL above is tricking Angular.

推荐答案

我最终得到来自AngularJS论坛答案。请参见详情此线程

I ended up getting the answer from AngularJS forum. See this thread for details

该链接到谷歌论坛线程，这是难以阅读，不提供一个明确的答案。要删除URL参数，用

The link is to a Google Groups thread, which is difficult to read and doesn't provide a clear answer. To remove URL parameters use

$location.url($location.path());

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