元组作为函数参数 [英] tuple as function argument

问题描述

如果可能如何使用可变参数元组作为函数的参数以及如何对其进行初始化，我会感到困惑。

I am a little confused if it possible an how to use a variadic tuple as an argument in a function and how to initialize it.

    template <typename T, Arg ...> 
      void foo (int a, std::tuple<T, sizeof(Arg)> TupleTest);
...

foo(TupleTest(2, "TEST", 5.5));

如何使用c ++ 0x来实现？

How could that be implemented using c++0x?

推荐答案

您不需要获取模板参数的数量。只需这样做：

You don't need to get the number of template arguments. Just do this:

template <typename... T>
void foo(int a, std::tuple<T...> TupleTest);

// make_tuple so we don't need to enter all the type names
foo(0, std::make_tuple(2, "TEST", 5.5));

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