在WinXP中如何隐藏进程窗口(从任务栏)来创建进程?与CreateProcess功能? [英] How could i Create a process with hiding the process window (from the task bar) in winXP? with CreateProcess function?
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问题描述
/* CreateProcess initialization */
STARTUPINFO si;
PROCESS_INFORMATION pi;
memset(&si, 0, sizeof(si));
memset(&pi, 0, sizeof(pi));
si.cb = sizeof(si);
long ret;
// si.wShowWindow = SW_HIDE;
// hide process window.... // run in background..
si.dwFlags = STARTF_USESHOWWINDOW;
si.wShowWindow = SW_HIDE;
if (!CreateProcess(0, exe,
0, 0, 1, NORMAL_PRIORITY_CLASS, 0, 0, &si, &pi)) {
return;
}
//int prez = WaitForSingleObject(pi.hProcess, INFINITE);
//CloseHandle(pi.hProcess);
推荐答案
您可以尝试设置dwFlags
成员rel = noreferrer> STARTUPINFO
结构到 STARTF_USESHOWWINDOW
和 wShowWindow
SW_HIDE
的成员。
You can attempt to set the dwFlags
member of your STARTUPINFO
structure to STARTF_USESHOWWINDOW
and the wShowWindow
member to SW_HIDE
.
这将使 CreateProcess()
传递0作为 WinMain
。但是,并非所有Windows应用程序的行为都很好,并在初始调用 ShowWindow()
时使用此值。
This will make CreateProcess()
pass 0 as the nCmdShow
parameter of WinMain
. However, not all Windows application are well behaved and use this value to the initial call to ShowWindow()
.
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