实现IEnumerable< T>在C ++ / CLI中 [英] Implementing IEnumerable<T> in C++/CLI
问题描述
在C ++ / CLI中的自定义集合类中实现 IEnumerable< T>
时遇到问题。这是代码的相关部分:
I'm having problems implementing IEnumerable<T>
in my custom collection class in C++/CLI. Here is the relevant part of the code:
using namespace System::Collections::Generic;
ref class MyCollection : IEnumerable<MyClass^>
{
public:
MyCollection()
{
}
virtual IEnumerator<MyClass^>^ GetEnumerator()
{
return nullptr;
}
};
编译时,会导致以下错误:
When compiled, this results in the following errors:
错误C2392:
'System :: Collections :: Generic :: IEnumerator
^ MyCollection :: GetEnumerator(void)':
协变量返回类型在托管类型中不支持
,否则
'System :: Collections :: IEnumerator
^ System :: Collections :: IEnumerable :: GetEnumerator(void)'
将被覆盖错误C3766:
'MyCollection'必须为接口
方法提供
实现
方法
'System :: Collections :: IEnumerator
^ System :: Collections :: IEnumerable :: GetEnumerator(void)'
error C2392: 'System::Collections::Generic::IEnumerator ^MyCollection::GetEnumerator(void)': covariant returns types are not supported in managed types, otherwise 'System::Collections::IEnumerator ^System::Collections::IEnumerable::GetEnumerator(void)' would be overridden error C3766: 'MyCollection' must provide an implementation for the interface method 'System::Collections::IEnumerator ^System::Collections::IEnumerable::GetEnumerator(void)'
这很有意义,因为 IEnumerable< T>
源自 IEnumerable
。但是,我不确定如何解决此编译错误。如果这是C#,我将隐式实现 IEnumerable
,但是我不确定如何在C ++ / CLI中做到这一点(如可能):
This makes sense, since IEnumerable<T>
derives from IEnumerable
. However, I'm not sure how to fix this compile error. If this was C#, I would implicitly implement IEnumerable
, however I'm not sure how to do that in C++/CLI (if that's even possible) like this:
class MyCollection : IEnumerable<MyClass>
{
public MyCollection()
{
}
public IEnumerator<MyClass> GetEnumerator()
{
return null;
}
System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
如果我添加了<$ c $的实现c> IEnumerable :: GetEnumerator(),编译器抱怨两个方法仅在返回类型上有所不同(这也很有意义)。
If I do add an implementation of IEnumerable::GetEnumerator()
, the compiler complains about two methods that differ only by return type (which also makes sense).
那么,如何在C ++ / CLI类中实现 IEnumerable< T>
?
So, how do I implement IEnumerable<T>
in a C++/CLI class?
推荐答案
您必须提供 the非通用GetEnumerator()方法,并包含非通用名称空间:
You must provide an explicit implementation of the non-generic GetEnumerator() method and include the non-generic namespace:
using namespace System::Collections;
....
virtual IEnumerator^ EnumerableGetEnumerator() = IEnumerable::GetEnumerator
{
return GetEnumerator<MyClass^>();
}
更新:如评论中所述, GetEnumerator的显式版本必须命名为不同名称以避免名称冲突,因此我将其命名为EnumerableGetEnumerator。
Update: As mentioned in the comments, the explicit version of GetEnumerator must be named different to avoid name clash, thus I've named it EnumerableGetEnumerator.
类似地,在C#中,您必须这样做: / p>
Similarly, in C# you would have to do it like this:
using System.Collections.Generic;
public class MyCollection : IEnumerable<MyClass>
{
public MyCollection()
{
}
public IEnumerator<MyClass> GetEnumerator()
{
return null;
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator<MyClass>();
}
}
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