很多登录代码 [英] Lots of Login Code

问题描述

这是一个相当长的问题，但我知道问题出在哪里。我正在使用CakePHP 2.0制作ajax登录脚本，但始终失败。我将发布我的所有代码，并希望有人有时间来阅读它。

This is a fairly long question but I have know idea where it's going wrong. I am making an ajax login script using CakePHP 2.0 but it keeps failing. I will post all of my code, and i hope someone has the time to go through it.

这是我的SQL数据库

AccountID   AccountEmail    AccountPassword  AccountActive  
1   [e-mail]     pass            0   
2   [e-mail]         pass            1 

这是我的相关标准代码

class Account extends AppModel {

public $name = 'Account';
public $validate = array(
    'AccountEmail' => array(
        'required' => array(
            'rule' => array('notEmpty'),
            'message' => 'Please Enter A Valid Email.'
        ),
        'email' => array(
            'rule'    => array('email', true),
            'message' => 'Please supply a valid email address.'
        )
    ),
    'AccountPassword' => array(
        'required' => array(
            'rule' => array('notEmpty'),
            'message' => 'Please Enter A Valid Password.'
        )
    )
);  
}

这是我相关的控制器代码

class AppController extends Controller {

/**
* Class Variables
*/
public $helpers = array('Js', 'Html', 'Session', 'Form');
public $components = array(
    'Session',
    'RequestHandler',
    'Auth' => array(
        'logoutRedirect' => array(
            'controller' => 'Accounts', 
            'action' => 'login'
        ),
        'authError' => 'You can\'t Access That Page',
        'authorize' => array('Controller'),
        'authenticate' => array(
            'Form' => array(
                'fields' => array(
                    'username' => 'AccountEmail', 
                    'password' => 'AccountPassword'
                ),
                'scope' => array('AccountActive' => '1')
            )
        )
    )
);
}

class AccountsController extends AppController {

/**
*   Class Variables 
*/
public $name = 'Accounts';
public $layout = 'Accounts';

/**
*   Class Functions 
*/
public function login()
{
    if ($this->request->is('ajax')) {
        $this->Account->set($this->data);
        if ($this->Account->validates()) {
            if($this->Auth->login()) {
                echo "logged In";
                exit;
            } else {
                echo "Login Failed";
                exit;
            }
        } else {
            echo 'validation/' . json_encode($this->Account->invalidFields());
            exit;
        }
    }
}

我认为没有还有什么。再次，我为海量的代码感到抱歉，但我只是不知道您需要什么。

信息全部通过'echo'传递给jquery，目前它只是通过显示响应'alert'。

我知道验证工作正常，但是如果我输入应该可以登录的人的信息，它只会显示登录失败。谢谢。

I don't think there is anything else. Again i'm sorry for the huge amount of code but i just don't know what you need.
The info is all passed via 'echo' to jquery which at the moment is just displaying the response via 'alert'.
I know the validation is working, but if i enter the info of someone who should be able to login it just shows "Login Failed". Thanks For Your Time.

推荐答案

您在数据库中的密码必须采用哈希形式。使用Cake的默认设置， 通过将为： 1c31af5bd9913ff511fe780f506e6fab68979b90

Your passwords in the database need to be in their hashed form. Using Cake's default settings, 'pass' would be: 1c31af5bd9913ff511fe780f506e6fab68979b90

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