如何使用Capybara使用查询字符串获取当前路径 [英] How to get current path with query string using Capybara
问题描述
页面url类似于 / people?search = name
,而我使用的是 current_path
方法的水豚只返回 / people
。
The page url is something like /people?search=name
while I used current_path
method of capybara it returned /people
only.
current_path.should == people_path(:search => 'name')
但没有说出
expected: "/people?search=name"
got: "/people"
如何使其通过?
推荐答案
我已经更新了此答案,以反映水豚的现代习俗。我认为这是理想的选择,因为这是公认的答案,而且在寻找解决方案时会提及许多人。话虽如此,检查当前路径的正确方法是使用Capybara提供的 has_current_path?
匹配器,如此处所述:单击此处
I've updated this answer to reflect modern conventions in capybara. I think this is ideal since this is the accepted answer, and what many people are being referred to when looking for a solution. With that said, the correct way to check the current path is to use the has_current_path?
matcher provided by Capybara, as documented here: Click Here
示例用法:
expect(page).to have_current_path(people_path(search: 'name'))
您可以在文档中看到其他选项。如果当前页面是 / people?search = name
,但是您只关心它在 / people
页面上参数,您可以发送 only_path
选项:
As you can see in the documentation, other options are available. If the current page is /people?search=name
but you only care that it's on the /people
page regardless of the param, you can send the only_path
option:
expect(page).to have_current_path(people_path, only_path: true)
另外,如果您想比较整个URL :
Additionally, if you want to compare the entire URL:
expect(page).to have_current_path(people_url, url: true)
Tom Walpole指出了这种方法。
Credit to Tom Walpole for pointing out this method.
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