区分大小写的文件扩展名和存在检查 [英] Case sensitive file extension and existence checking
问题描述
我需要检查文件是否存在。这可以通过 File#exists()
方法完成。但是这种存在检查是区分大小写的。我的意思是,如果我在代码中有一个文件名some_image_file.jpg,但是实际上如果文件是some_image_file.JPG,则此方法表示该文件不存在。
I need to check whether or not a file exists. Which can be accomplished by File#exists()
method. But this existence checking is case sensitive. I mean if I have a file name some_image_file.jpg in code but if physically the file is some_image_file.JPG then this method says that the file doesn't exists. How can I check the file existence with case insensitivity to the extension and get the actual file name?
在我的情况下,我有一个excel文件,如何检查扩展名不区分大小写的文件是否存在并获得实际的文件名?每行包含文件和文件名的元数据。在某些情况下,我只有文件名,而在其他情况下,我可以拥有完整路径。我将一行表示为文档。
In my scenario, I have a excel file. Each row contains metadata for files and the filename. In some cases I have only the filename or other cases I can have full path. I am denoting a row as a document.
这些文件放在服务器中。我的工作是
These files are placed in the server. My job is to
- 逐行读取excel文件并列出所有文档。
- 取出文件名或文件路径。
- 创建文件的完整路径。
- 检查文件是否存在。
- 验证文档中提供的其他元数据/信息。
- 上传文件。
- Read the excel file row by row and list all the documents.
- Take out the filename or filepath.
- Create the full path of the file.
- Check if the file exists or not.
- Validate other metadata/information provided in the document.
- Upload the file.
如果文件不存在或某些元数据无效,我的应用程序将引发异常。
My application throws exception in case the file doesn't exists or if some metadata are invalid.
excel文件由客户,他们写了一些错误的文件名,我的意思是,如果文件实际具有小写扩展名,则以大写形式写扩展名,反之亦然。
The excel file is written by the customer and they wrote some file name wrong, I mean if the file physically have the extension in lower case, they have written the extension in upper case, also the converse is true.
我正在Unix服务器上运行应用程序。
I am running the application in unix server.
由于文件扩展名不匹配,因此 File#exists()
给出错误信息,最终我的代码引发异常。
As the file extensions are not matching so the File#exists()
is giving false and eventually my code is throwing exception.
放置文件的文件夹可以包含30000个或更多文件。
The folders where the files are placed can have 30000 or more files.
我想要的是
- 获取文件的完整路径。
- 检查文件是否存在。
- 如果文件不存在,则
- 检查文件是否存在b y转换扩展名的大小写。
- 如果大小写转换后不存在扩展名,则抛出异常。
- 如果存在,则返回实际文件名或文件路径。
- To take the full path of the file.
- Check if the file exists or not.
- If it does not exists then
- Check the file existence by converting the case of the extension.
- If it doesn't exist after the case conversion then throw exception.
- If it exists, then return the actual file name or file path.
如果文件名具有文件扩展名,例如 .jpg ,不知道该怎么办!我应该通过更改大小写来检查它吗?
If the file name has file extension something like .Jpg, don't know what to do! Should I check it by permuting it by changing the case?
推荐答案
这样我已经解决了问题:
This way I had solved the problem:
public String getActualFilePath() {
File givenFile = new File(filePath);
File directory = givenFile.getParentFile();
if(directory == null || !directory.isDirectory()) {
return filePath;
}
File[] files = directory.listFiles();
Map<String, String> fileMap = new HashMap<String, String>();
for(File file : files) {
if(file.isDirectory()){
continue;
}
String absolutePath = file.getAbsolutePath();
fileMap.put(absolutePath, StringUtils.upperCase(absolutePath));
}
int noOfOcc = 0;
String actualFilePath = "";
for(Entry<String, String> entry : fileMap.entrySet()) {
if(filePath.toUpperCase().equals(entry.getValue())) {
actualFilePath = entry.getKey();
noOfOcc++;
}
}
if(noOfOcc == 1) {
return actualFilePath;
}
return filePath;
}
此处 filePath
是文件的完整路径。
Here filePath
is the full path to the file.
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