如何在CHEF（Ruby）中创建漂亮的json [英] How do you create pretty json in CHEF (ruby)

问题描述

您将如何制作一个具有人类可读json的erb模板？

How would you make an erb template that has human readable json?

以下代码可以正常工作，但是可以创建一个平面json文件

The following code works, but it makes a flat json file

default.rb

default.rb

default['foo']['bar'] = { :herp => 'true', :derp => 42 }

recipe.rb

recipe.rb

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => node['foo']['bar'].to_json
  action :create
end

foo.json.erb

foo.json.erb

<%= @settings %>

类似的SO问题

Chef和ruby模板-如何遍历键值对？

如何漂亮

推荐答案

此SO Answer .erb模板适用于HTML和XML，但不适用于json。

As pointed out by this SO Answer .erb templates are great for HTML, and XML, but is not good for json.

幸运的是，CHEF使用了它的拥有自己的json库，它使用 .to_json_pretty

Luckily, CHEF uses its own json library which has support for this using .to_json_pretty

本文将更广泛地显示如何在食谱中使用厨师助手。

@coderanger in IRC, pointed out that you can use this library right inside the recipe. This article shows more extensively how to use chef helpers in recipes.

default.rb

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

食谱/foo.rb

pretty_settings = Chef::JSONCompat.to_json_pretty(node['foo']['bar'])

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => pretty_settings
  action :create
end

---

YMMV指出的或更简洁

---

Or more concise as pointed out by YMMV

default.rb

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

recipe / foo.rb

recipe/foo.rb

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => node['foo']['bar']
  action :create
end

templates / foo.json.erb

templates/foo.json.erb

<%= Chef::JSONCompat.to_json_pretty(@settings) %>

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