jQuery的$ .MAP角相同呢? [英] Angular equivalent of jQuery $.map?

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本文介绍了jQuery的$ .MAP角相同呢?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我是从依靠jQuery来开发应用程序在AngularJS过渡。我们建议在<一个href=\"http://stackoverflow.com/questions/14994391/how-do-i-think-in-angularjs-if-i-have-a-jquery-background\">number地方来的的混合jQuery和角code。

I'm transitioning from relying on jQuery to building apps in AngularJS. It's recommended in a number of places to not mix jQuery and Angular code.

有一件事情我很想念虽然是jQuery的$ .MAP数组功能。我知道这可能是使用原生的JavaScript 地图功能重新编写,不过这在所有浏览器未实现。(值得注意的是,IE&LT; V9)

One thing I miss though is the jQuery $.map function for arrays. I know this could be re-written using the native Javascript map function, but this is not implemented in all browsers (notably, IE < v9).

那么,有没有一个角相等的,或者我应该回来编写为(VAR X = 0; X&LT;富; X + = 1){...} 这样我就可以停止包括jQuery的?

So, is there an Angular equivalent, or should I got back to writing for (var x = 0; x < foo; x += 1) {...} so I can stop including jQuery?

更新有时知道该怎么寻找是所有你需要。 Bergie说:找polyfills。这里有一个参考指南(从Modernizr的船员)的大量资源制造对旧的浏览器现代化code的工作:的 HTML5跨浏览器Polyfills

UPDATE Sometimes knowing what to search for is all you need. Bergie says 'look for polyfills'. Here's a reference guide (from the Modernizr crew) for a bunch of resources for making modern code work on older browsers: HTML5 Cross Browser Polyfills

推荐答案

查看此处:<一href=\"https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/map\">https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/map

Mozilla已经提供的Array.map填充工具不支持的浏览器

Mozilla has supplied an Array.map polyfill for unsupported browsers

if (!Array.prototype.map) {
  Array.prototype.map = function(callback, thisArg) {

    var T, A, k;

    if (this == null) {
      throw new TypeError(" this is null or not defined");
    }

    // 1. Let O be the result of calling ToObject passing the |this| value as the argument.
    var O = Object(this);

    // 2. Let lenValue be the result of calling the Get internal method of O with the argument "length".
    // 3. Let len be ToUint32(lenValue).
    var len = O.length >>> 0;

    // 4. If IsCallable(callback) is false, throw a TypeError exception.
    // See: http://es5.github.com/#x9.11
    if (typeof callback !== "function") {
      throw new TypeError(callback + " is not a function");
    }

    // 5. If thisArg was supplied, let T be thisArg; else let T be undefined.
    if (thisArg) {
      T = thisArg;
    }

    // 6. Let A be a new array created as if by the expression new Array(len) where Array is
    // the standard built-in constructor with that name and len is the value of len.
    A = new Array(len);

    // 7. Let k be 0
    k = 0;

    // 8. Repeat, while k < len
    while(k < len) {

      var kValue, mappedValue;

      // a. Let Pk be ToString(k).
      //   This is implicit for LHS operands of the in operator
      // b. Let kPresent be the result of calling the HasProperty internal method of O with argument Pk.
      //   This step can be combined with c
      // c. If kPresent is true, then
      if (k in O) {

        // i. Let kValue be the result of calling the Get internal method of O with argument Pk.
        kValue = O[ k ];

        // ii. Let mappedValue be the result of calling the Call internal method of callback
        // with T as the this value and argument list containing kValue, k, and O.
        mappedValue = callback.call(T, kValue, k, O);

        // iii. Call the DefineOwnProperty internal method of A with arguments
        // Pk, Property Descriptor {Value: mappedValue, : true, Enumerable: true, Configurable: true},
        // and false.

        // In browsers that support Object.defineProperty, use the following:
        // Object.defineProperty(A, Pk, { value: mappedValue, writable: true, enumerable: true, configurable: true });

        // For best browser support, use the following:
        A[ k ] = mappedValue;
      }
      // d. Increase k by 1.
      k++;
    }

    // 9. return A
    return A;
  };      
}

这篇关于jQuery的$ .MAP角相同呢?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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