使用VLC的虚拟界面时如何防止显示控制台 [英] How to prevent console from being displayed when using VLC's dummy interface

问题描述

我正在尝试从Node.js服务器脚本以虚拟模式启动VLC，但是使用 child_process.spawn（'vlc'，['-I dummy']）会为VLC的输出生成一个新的控制台窗口。有没有办法防止这种情况发生，并通过stdout ReadableStream强制所有stdout，这样就不会出现弹出窗口？

I'm trying to launch VLC in "dummy" mode from a Node.js server script, however using child_process.spawn('vlc',['-I dummy']) produces a new console window for VLC's output when using Windows. Is there a way to prevent this happening and force all stdout though the stdout ReadableStream so no "popup windows" occur?

EDIT ：此问题与node.js无关，这只是我所说的方式以及VLC的行为。解决方案如下。

EDIT: This problem had nothing to do with node.js, it was simply the way I was calling it and VLC's behaviour. The solution is below.

谢谢。

推荐答案

我发现了一个特定问题的解决方案：

I found a solution for the specific problem:

VLC有一个命令行选项可以隐藏此窗口-*-quiet其中*是接口。

VLC has a command line option to surpress this window --*-quiet where * is the interface.

例如对于虚拟界面，请使用

e.g. For the dummy interface, use

child_process.spawn('vlc',['-I dummy','--dummy-quiet'])

对于rc接口，请使用

child_process.spawn('vlc',['-I rc','--rc-quiet'])

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