在另一个输入请求之前清除cin缓冲区，c ++ [英] Clear the cin buffer before another input request, c++

问题描述

我有以下代码：

int choice = 0;
char st1[N];

cout << "enter choice" <<endl;
cin >> choice;

cout << "enter sentence" << endl;
cin.get(st1, N-1);

到cin.get行时，无论输入是什么，它都将显示为\0将char转换为st1 [0]
就是这样。

when getting to cin.get line, no matter what the input is, it will read \0 char into st1[0] and that's it.

我认为它与最新的cin有关（到选择变量中）。

I assume it has something to do with the latest cin ( into choice variable ).

我如何在从用户那里获得新输入之前清洗 cin缓冲器？

How do i "clean" cin buffer before getting new input from the user? if that's possible.

谢谢

推荐答案

您可以使用忽略以便从缓冲区中删除换行符（例如，将X字符删除为换行符定界符）。

You might use ignore to drop the newline from the buffer (e.g. drop X characters before the newline as delimiter). Extraction and ignore stop when the delimiter is extracted.

例如

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

也相关：

Also related: Why would we call cin.clear() and cin.ignore() after reading input?

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