空间问题 [英] cin issue with space

问题描述

所以我试图从cin读取一些内容，并用空格将它们切开，例如

So I was trying to read something from cin and spaces cut them, For example, if I got

AA 3 4 5
111 222 33

来自cin，我想将它们存储在字符串数组。
到目前为止，我的代码是

from cin, I want to store them in a string array. My code so far is

string temp;
int x = 0;
string array[256];
while(!cin.eof())
{
    cin >> temp;
    array[x] = temp;
    x += 1;
}

，但是程序崩溃了。
然后我添加了cout来尝试弄清楚温度是什么，它显示：

but then the program crashed. Then I added cout to tried figure out what is in temp and it shows:

AA345

那么我如何将输入存储到带有空格的输入数组中呢？

So how can I store the input into an array with spaces cutting them?

推荐答案

这里有一种可能性，可以处理 cin 中的输入，并在条目之间使用任意数量的空格，并存储通过使用Boost库在矢量中获取数据：

Here's one possibility to treat an input from cin with an arbitrary number of whitespaces between the entries, and to store the data in a vector by using the boost library:

#include <iostream>
#include <string>
#include <vector>
#include <boost/algorithm/string.hpp>
int main() {
  std::string temp;
  std::vector<std::string> entries;
  while(std::getline(std::cin,temp)) {  
      boost::split(entries, temp, boost::is_any_of(" "), boost::token_compress_on);
      std::cout << "number of entries: " << entries.size() << std::endl;
      for (int i = 0; i < entries.size(); ++i) 
        std::cout << "entry number " << i <<" is "<< entries[i] << std::endl;                  
    }  
  return 0;
}

编辑

无需使用令人敬畏的增强库即可获得相同的结果，例如，通过以下方式：

The same result could be obtained without using the awesome boost library, e.g., in the following way:

#include <iostream>
#include <string>
#include <vector>
#include <sstream>
int main() {
  std::string temp;
  std::vector<std::string> entries;
  while(std::getline(std::cin,temp)) {    
      std::istringstream iss(temp);
      while(!iss.eof()){ 
        iss >> temp;
        entries.push_back(temp);    
      }
      std::cout << "number of entries: " << entries.size() << std::endl;
      for (int i = 0; i < entries.size(); ++i)  
        std::cout<< "entry number " << i <<" is "<< entries[i] << std::endl;
      entries.erase(entries.begin(),entries.end()); 
    }
  return 0;
}

示例

输入：

AA 12  6789     K7

输出：

number of entries: 4
entry number 0 is AA
entry number 1 is 12
entry number 2 is 6789
entry number 3 is K7

希望这会有所帮助。

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