量角器检查元素不存在 [英] Protractor Check if Element Does Not Exist

问题描述

我在我的角度基于网站，打开一个下拉和关闭的设置。如果处于关闭状态，那么它不会显示在主页上。

I have a setting in my angular based website that turns a dropdown on and off. If it is off, then it does not show on the main page.

使用量角器，我需要检查，看看这个元素不是present当开关处于关闭状态。但是，我不应该被扔到元未找到错误，因为它是在一组的一处试验。我应该怎么做呢？

With Protractor, I need to check to see if this element is not present when the switch is off. However, I should not be thrown into Element Not Found Error, as it is one test in a set of many. How should I do this?

我试图做：

expect($$('.switch').count()).to.equal(0).and.notify(next);

不过，我得到一个AssertionError这个...

But I am getting an AssertionError with this...

推荐答案

得到的东西通过我的东西在该文档中找到工作：

Got the thing working by using something I found in the docs:

expect(element(by.css('.switch')).isPresent()).to.become(false).and.notify(next);

还采用断言，所以它不会破坏cucumberjs。

Also uses assertions, so it doesn't break cucumberjs.

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